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patriot [66]
4 years ago
12

The table above shows data collected on five apples while doing field research outside the laboratory. What type of lab equipmen

t was used to collect the data in the table?
A) microscope


B) thermometer


C) metric ruler


D) gram spring scale



apples / weight, in mass


Apple 1 / 154 grams

Apple 2 / 178 grams

Apple 3 / 151 grams

Apple 4 / 163 grams

Apple 5 l 170 grams
Chemistry
2 answers:
nalin [4]4 years ago
7 0
D a gram scale would measure grams
anastassius [24]4 years ago
6 0

Answer:

D) gram spring scale

Explanation:

In this experiment, the property that was measured is mass, we know that because grams are units of mass.

The laboratory equipment that measures mass are scales.

A microscope allows you to see objects that are small, but it doesn't measure mass.

A thermometer measures temperature

A metric ruler measures length.

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2. if 0.20 m fe3 had been used instead of 0.020 m fe3 , how would the numerical value of the rate constant and the activation en
dezoksy [38]

the calculated value is Ea is 18.2 KJ and A is 12.27.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

At 500K, K=0.02s−1

At 700K, k=0.07s −1

The Arrhenius equation can be used to calculate Ea and A.

RT=k=Ae Ea

lnk=lnA+(RT−Ea)

At 500 K,

ln0.02=lnA+500R−Ea

500R Ea (1) At 700K lnA=ln (0.02) + 500R

lnA = ln (0.07) + 700REa (2)

Adding (1) to (2)

700REa100R1[5Ea-7Ea] = 0.02) +500REa=0.07) +700REa.

=ln [0.02/0 .07]

Ea= 2/35×100×8.314×1.2528

Ea =18227.6J

Ea =18.2KJ

Changing the value of E an in (1),

lnA=0.02) + 500×8.314/18227.6

= (−3.9120) +4.3848

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logA=1.0889

A=antilog (1.0889)

A=12.27

Consequently, Ea is 18.2 KJ and A is 12.27.

Learn more about Arrhenius equation here-

brainly.com/question/12907018

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