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Salsk061 [2.6K]
3 years ago
6

Is this equation balanced and in lowest form? 4NH➡ 2N² + 6H²

Chemistry
1 answer:
cestrela7 [59]3 years ago
7 0
The given gives an equation <span>4NH➡ 2N² + 6H². The equation given is not correct since H is not balanced. on the right side,H is counted as only 4 while on the right side, H is 12. The compound on the right should be ammonia, NH3 in order to balance the equation.</span>
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One of the reasons that stars are so large is because _____.
ValentinkaMS [17]

Answer:

They are composed of hydrogen and helium

4 0
3 years ago
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Here's the question ~
Lelechka [254]

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

  • Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

RH = Rydberg constant

nf = final state

ni = initial state

  • When final state = 3 and initial state = ∞

Then;

1/λ =  1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

1/λ =  1 × 10^7 m-1 (1/3^2 )

λ = 900 nm

Hence, the correct answer is Paschen, ∞ → 3

Learn more about the Rydberg formula; brainly.com/question/17753747

3 0
2 years ago
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Proszę napisać wzór kwasu karboksylowego o 7 atomach węgla sumaryczny i strukturalny.
Mice21 [21]

Answer:

Explanation:

Carboxylic acids is a homologous series in which the compounds contain a functional group called the carboxyl group (-COOH). The general molecular formula for carboxylic acids is CnH2n+1COOH. Carboxylic acids contain at least one carboxyl group.

Or in Polish…

Kwasy karboksylowe to homologiczna seria, w której związki zawierają grupę funkcyjną zwaną grupą karboksylową (-COOH). Ogólny wzór cząsteczkowy dla kwasów karboksylowych to CnH2n + 1COOH. Kwasy karboksylowe zawierają co najmniej jedną grupę karboksylową.

8 0
3 years ago
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda
DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = \frac{5}{100}=0.05

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = \frac{95}{100}=0.95

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(113\times 0.05)+(115\times 0.95)]

A=114.9amu

Thus its average atomic mass is 114.9 amu

5 0
3 years ago
What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?
Butoxors [25]
Mg(NO3)2 ➡️ Mg2+ + 2 NO3-

(32.0g Mg(NO3)2) / (148.3g Mg(NO3)2/mol)* (2 mol NO3- / 1 mol Mg(NO3)2) / (0.425 L) = 1.02 mol/ L NO3-
6 0
3 years ago
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