1) Compund Ir (x) O(y)
2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g
3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g
4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g
5) Convert grams to moles
moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles
moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131
6) Find the proportion of moles
Divide by the least of the number of moles, i.e. 0.00656
Ir: 0.00656 / 0.00656 = 1
O: 0.0131 / 0.00656 = 2
=> Empirical formula = Ir O2 (where 2 is the superscript for O)
Answer: Ir O2
<span>Explain the difference between a weak acid and a strong acid according to the Arrhenius theory his question in english</span>
Answer:
Formula of the compound = 
Explanation:
Given,
No. of mole of O = 8.20 mol
No. of mole of P = 3.30 mol
Chemical formula = 
Ratio of P and O = 
formula of the compound =
There can only be two electrons in the innermost shell of an atom so b is the correct answer
Answer:
a free swimming larval stage in which a parasitic fluke passes from an intermediate host to another intermediate host
