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ivolga24 [154]
3 years ago
15

Consider a series of molecules in which the C atom is bonded to atoms of second-period elements: C-O, C-F, C-N, C-C, and C-B. Pl

ace these bonds in order of decreasing bond length.
Chemistry
1 answer:
Sati [7]3 years ago
8 0

Answer:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Explanation:

As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>

The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.

With that information in mind, and looking at the periodic table, the order would be:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Where the C-F bond is the shortest among them.

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Answer:

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Explanation:

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5 0
2 years ago
What are the roles of producers, primary consumers, secondary consumers, tertiary consumers for the trophic levels in the energy
Nesterboy [21]
     This question is more for Biology than Chemistry, but the role of producers is to make energy (food) to be consumed. In a pyramid diagram, the producers would be at the bottom. Now going up the pyramid, the primary conumers are the first to consume producers and obtain energy from them. As you go up the pyramid, the secondary consumers will consume the primary consumers as a way to obtain energy, and the same goes for tertiary consumers towards secondaries.

As you go up the energy pyramid, you will notice a trend that there is less energy being obtained from each consumer. In other words, the producers will ALWAYS have more energy than the tertiary consumers.

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3 0
3 years ago
The boiling point of a solution with a non-volatile solute is higher than that of the pure solvent . True or false
RUDIKE [14]
True because
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6 0
3 years ago
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th
oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , n=\dfrac{2.666}{16}=0.167\ mole .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , m=12\times 0.167=2\ g .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

5 0
3 years ago
What is true about energy?
xeze [42]
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7 0
3 years ago
Read 2 more answers
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