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ivolga24 [154]
3 years ago
15

Consider a series of molecules in which the C atom is bonded to atoms of second-period elements: C-O, C-F, C-N, C-C, and C-B. Pl

ace these bonds in order of decreasing bond length.
Chemistry
1 answer:
Sati [7]3 years ago
8 0

Answer:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Explanation:

As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>

The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.

With that information in mind, and looking at the periodic table, the order would be:

  1. C-B
  2. C-C
  3. C-N
  4. C-O
  5. C-F

Where the C-F bond is the shortest among them.

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