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Murljashka [212]
3 years ago
11

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 72.7 m/s2

for 1.79 seconds, at which point its fuel abruptly runs out. Air resistance has no effect on its flight. What maximum altitude (above the ground) will the rocket reach?

Physics
1 answer:
____ [38]3 years ago
4 0

Answer:

amplitude = 72.7× 1.79 = 130.133 m

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Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
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Answer:

Plss see attached file

Explanation:

3 0
3 years ago
Give an example of a scientific hypothesis. Explain how you would test it, and how it could be falsified (proved untrue).
kaheart [24]

my hypothesis is that If you drop a piece of buttered toast, it will land butter side down.


I tested it by dropping 10 pieces of buttered toast off the table and noted on which side it landed


It could be falsified cause I just made all of this up. In essence, it's like flipping a coin, 50/50 chance so I could say that 5 landed butter up and 5 landed butter down.

8 0
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If a pitcher throws a baseball 10 m in 30 seconds - what would be the average speed?
allsm [11]

Answer:

0.333 m/s

Explanation:

avg speed= (total distance)/(total time)

10m/30s

0.333 m/s

7 0
3 years ago
Read 2 more answers
A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni
ad-work [718]

Answer:

The magnetic force on the section of wire is -2.925\hat{j}\ N.

Explanation:

Given that,

Current I = 2.60\hat{i}\ A

Length = 0.750 m

Magnetic field B = 1.50\hat{k}\ T

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

\vec{F}=l\vec{I}\times\vec{B}

\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}

Since, \hat{i}\times\hat{k}=-\hat{j}

\vec{F}=-2.925\hat{j}\ N

Hence, The magnetic force on the section of wire is -2.925\hat{j}\ N.

7 0
3 years ago
An example of when total internal reflection occurs is when all the light passing from a region of higher index of refraction to
Amiraneli [1.4K]

Answer:

is reflected back into the region of higher index

Explanation:

Total internal reflection is a phenomenon that occurs when all the light passing from a region of higher index of refraction to a region of lower index is reflected back into the region of higher index.

According to Snell's law, refraction of ligth is described by the equation

n_1 sin \theta_1 = n_2 sin \theta_2

where

n1 is the refractive index of the first medium

n2 is the refractive index of the second medium

\theta_1 is the angle of incidence (in the first medium)

\theta_2 is the angle of refraction (in the second medium)

Let's now consider a situation in which

n_1 > n_2

so light is moving from a medium with higher index to a medium with lower index. We can re-write the equation as

sin \theta_2 = \frac{n_1}{n_2}sin \theta_1

Where \frac{n_1}{n_2} is a number greater than 1. This means that above a certain value of the angle of incidence \theta_1, the term on the right can become greater than 1. So this would mean

sin \theta_2 > 1

But this is not possible (the sine cannot be larger than 1), so no refraction occurs in this case, and all the light is reflected back into the initial medium (total internal reflection). The value of the angle of incidence above which this phenomen occurs is called critical angle, and it is given by

\theta_c =sin^{-1}(\frac{n_2}{n_1})

8 0
3 years ago
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