That would be C .............
The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
<h3>What is impedance Z of the circuit?</h3>
The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.
Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.
A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.
The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,
The impedance Z of the circuit is,
Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.
Learn more about the impedance Z of the circuit here:
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B. 500ft. If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.
Answer:
The third shell would be empty, so the eight electrons on the second level would be the outermost after the atom lost one electron
Explanation:
When an atom is bonded with other atoms, a more stable configuration must be reached, which is why the energy of the molecule is less than the energy of the individual atoms, for this to happen in general, electrons are shared or lost and gained in each atom, depending on the electronegative of the same.
If we analyze an atom within the molecule, its last shell is full, in the case of atoms with few electrons in this shell, they are lost and in the case of many electors in this shell, it gains electrons to have eight (8) in total.
When reviewing the different answers, the correct one is:
* The third shell would be empty, so the eight electrons on the second level would be the outermost after the atom lost one electron
Mechanical energy (ME) is the sum of potential energy (PE) and kinetic energy (KE). When the toy falls, energy is converted from PE to KE, but by conservation of energy, ME (and therefore PE+KE) will remain the same.
Therefore, ME at 0.500 m is the same as ME at 0.830 m (the starting point). It's easier to calculate ME at the starting point because its just PE we need to worry about (but if we wanted to we could calculate the instantaneous PE and KE at 0.500 m too and add them to get the same answer).
At the start:
ME = PE = mgh
ME = 0.900 (9.8) (0.830)
ME = 7.32 J
