Take the moment car A starts to accelerate to be the origin. Then car A has position at time <em>t</em>
<em>x</em> = (20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>²
and car B's position is given by
<em>x</em> = 300 m + (27.0 m/s) <em>t</em>
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Car A overtakes car B at the moment their positions are equal:
(20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>² = 300 m + (27.0 m/s) <em>t</em>
300 m + (7.00 m/s) <em>t</em> - (1.05 m/s²) <em>t</em>² = 0
==> <em>t</em> ≈ 20.6 s
Answer:
numerical measurement of how far apart objects or points are.
Explanation:
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Answer:
Horizontal component, 
Explanation:
It is given that,
Displacement of the submarine, d = 185 m
It is at an angle of 15 degrees below the horizontal. We need to find the horizontal component of the submarine's displacement. It is given by :

Substituting the values in above equation as :


So, the horizontal component of the submarine’s displacement is 178.69 meters. Hence, this is the required solution.