All categories

3 years ago

If a pitcher throws a baseball 10 m in 30 seconds - what would be the average speed?

Physics

2 answers:

allsm [11]3 years ago

7 0

Answer:

0.333 m/s

Explanation:

avg speed= (total distance)/(total time)

10m/30s

0.333 m/s

dedylja [7]3 years ago

4 0

0.333 m/s is not the answer

You might be interested in

An electric current is passed through water and bubbles start forming.What is a logical conclusion for the bubbles?

Nezavi [6.7K]

Hydrogen and oxygen are being formed if an <span>electric current is passed through water and bubbles start forming.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>

7 0

3 years ago

Read 2 more answers

A ball is thrown so that its initial vertical and horizontal components of velocity are 30 m/s and 15 m/s, respectively. Estimat

mihalych1998 [28]

Answer:

H = 45 m

Explanation:

First we find the launch velocity of the ball by using the following formula:

v₀ = √(v₀ₓ² + v₀y²)

where,

v₀ = launching velocity = ?

v₀ₓ = Horizontal Component of Launch Velocity = 15 m/s

v₀y = Vertical Component of Launch Velocity = 30 m/s

Therefore,

v₀ = √[(15 m/s)² + (30 m/s)²]

v₀ = 33.54 m/s

Now, we find the launch angle of the ball by using the following formula:

θ = tan⁻¹ (v₀y/v₀ₓ)

θ = tan⁻¹ (30/15)

θ = tan⁻¹ (2)

θ = 63.43°

Now, the maximum height attained by the ball is given by the formula:

H = (v₀² Sin² θ)/2g

H = (33.54 m/s)² (Sin² 63.43°)/2(10 m/s²)

6 0

3 years ago

The lever shown above can be used to move the

vladimir1956 [14]

Answer:

C your answer would be C

Explanation:

It should be right

4 0

3 years ago

What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2

aev [14]

Mass=m=142kg
Acceleration=a=30m/s
Force=F

Using Newton's second law

$\\ \sf\Rrightarrow F=ma$

$\\ \sf\Rrightarrow F=142(30)$

$\\ \sf\Rrightarrow F=4260N$

7 0

3 years ago

An artist working on a piece of metal in his forging studio plunges the hot metal into oil in order to harden it. The metal piec

lutik1710 [3]

Answer:

The temperature of the metal is $T_m = 376.8 ^o C$

Explanation:

From the question we are told that

The mass of the metal is $M = 60 \ kg$

The specific heat of the metal is $c_p = 0.1027 kcal/(kg \cdot ^oC)$

The mass of the oil is $M_o = 810 \ kg$

The temperature of the oil is $T_o = 35^oC$

The specific heat of oil is $c_o = 0.7167 kcal/(kg \cdot ^oC )$

The equilibrium temperature is $T_e = 39 ^oC$

According to the law of energy conservation

Heat lost by metal = heat gained by the oil

The quantity of heat lost by the metal is mathematically represented as

$Q = - Mc_p \Delta T$

=> $Q = -Mc_p (T_m - T_c)$

Where $T_ m$ the temperature of metal before immersion

The negative sign show heat lost

The quantity of gained t by the metal is mathematically represented as

$Q = M_o c_o \Delta T$

=> $Q = M_o c_o (T_c - T_o)$

$Mc_p (T_m - T_c) = M_o c_o (T_c - T_o)$

substituting values

$- 60 * 0.1027 (T_m - 39) = 810 * 0.7167 * (39 - 35)$

=> $T_m = 376.8 ^o C$

6 0

3 years ago