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vesna_86 [32]
3 years ago
8

If a pitcher throws a baseball 10 m in 30 seconds - what would be the average speed?

Physics
2 answers:
allsm [11]3 years ago
7 0

Answer:

0.333 m/s

Explanation:

avg speed= (total distance)/(total time)

10m/30s

0.333 m/s

dedylja [7]3 years ago
4 0
0.333 m/s is not the answer
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Violet light of wavelength 400 nm ejects electrons with a maximum kinetic energy of 0.860 eV from sodium metal. What is the bind
Travka [436]

Answer:

Binding Energy = 2.24 eV

Explanation:

First, we need to find the energy of the photon of light:

E = hc/λ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light = 400 nm = 4 x 10⁻⁷ m

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(4 x 10⁻⁷ m)

E = (4.97 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)

E = 3.1 eV

Now, from Einstein's Photoelectric Equation:

E = Binding Energy + Kinetic Energy

Binding Energy = E - Kinetic Energy

Binding Energy = 3.1 eV - 0.86 eV

<u>Binding Energy = 2.24 eV</u>

4 0
3 years ago
Brainliest for correct answer! :)
Katena32 [7]

Answer:

1. 300.15

2. 873.15

3. 221.95

1. -243.15

2. -210.85

3. 295.17

5 0
3 years ago
A car is traveling with a constant speed when the driver suddenly applies the brakes, causing the car to slow down with a consta
Margaret [11]
Consider a car<span> that travels between points A and B. The </span>car's<span> average </span>speed<span> can be ..... the </span>car<span> to </span>slow down<span> with a </span>constant acceleration<span> of </span>magnitude 3.50 m/s2<span>. </span>If<span> the </span>car comes<span> to a </span>stop<span> in a </span>distance<span> of</span>30.0 m<span>, what was the </span>car's original speed<span>? ... A </span>car<span> is </span>traveling<span> at 26.0 </span>m<span>/s when the </span>driver suddenly applies<span> the </span>brakes<span>, ...</span>
4 0
3 years ago
A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per
FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

4 0
2 years ago
For a snowboard jumper in the air, what force or forces will be most important for modeling the motion?
Reptile [31]

Answer: Gravitational force and drag force

Explanation:

For a snowboard jumper in the air, two forces would be acting. One in the downward direction- the gravitational pull and second in the opposite direction to the motion, the drag force due to air. If the snowboard jumper jumps in the air at a certain angle with the horizontal. The forces are written as the sum of vertical and horizontal components. Hence, for the modeling the motion, gravitational force and drag force are important,

4 0
2 years ago
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