There are 100cm in one metre. Hence, divide 100 by 550 to figure out for much 550cm is in meters. It is 5.5m.
Answer:
.
Explanation:
Power carried by the line ![=P=450 \mathrm{MW}=450 \times 10^{6} \mathrm{~W}](https://tex.z-dn.net/?f=%3DP%3D450%20%5Cmathrm%7BMW%7D%3D450%20%5Ctimes%2010%5E%7B6%7D%20%5Cmathrm%7B~W%7D)
Voltage across the line Volts
Current flowing in the line =i
Size of magnetic field =B
Distance from the line
Formula Used:
Current flowing is given as
![i=\frac{P}{\Delta V}](https://tex.z-dn.net/?f=i%3D%5Cfrac%7BP%7D%7B%5CDelta%20V%7D)
Magnetic field by the current carrying wire is given as
![B=\left(\frac{\mu}{4 \pi}\right)\left(\frac{2 i}{r}\right)](https://tex.z-dn.net/?f=B%3D%5Cleft%28%5Cfrac%7B%5Cmu%7D%7B4%20%5Cpi%7D%5Cright%29%5Cleft%28%5Cfrac%7B2%20i%7D%7Br%7D%5Cright%29)
Inserting the values
![B=\left(10^{-7}\right)\left(\frac{2(1500)}{(20)}\right) \\ B=1.5 \times 10^{-5} \mathrm{~T}](https://tex.z-dn.net/?f=B%3D%5Cleft%2810%5E%7B-7%7D%5Cright%29%5Cleft%28%5Cfrac%7B2%281500%29%7D%7B%2820%29%7D%5Cright%29%20%5C%5C%0AB%3D1.5%20%5Ctimes%2010%5E%7B-5%7D%20%5Cmathrm%7B~T%7D)
Conclusion:
Thus, the magnetic field comes out to be
.
Wavelength × frequency = speed
Answer:
Comets
Explanation:
Comets are planetary celestial bodies consisting of ice and dust, sometimes rocky particles formed in the region of the solar system. Long-period comets propagate towards the Sun by gravitational perturbations caused by passing stars. Some comets usually hyberbolic comets, move through the inner Solar System prior to entering the interstellar region. Short period comet lies beyond the orbit of the Neptune.
The Jovian planets include Jupiter, Saturn, Uranus, and Neptune.
Therefore, leftovers of comets (planetesimal bodies) formed in the region of the solar system that are now occupied by the Jovian planets is due to the dusty particles associated with the comets.
Answer:
The magnification is ![m = 0.3674](https://tex.z-dn.net/?f=m%20%20%3D%200.3674)
Explanation:
From the question we are told that
The power of the lens is ![P = -4.00 D(dioptre)](https://tex.z-dn.net/?f=P%20%3D%20-4.00%20D%28dioptre%29)
Generally ![1 dioptre = 1 \ meter](https://tex.z-dn.net/?f=1%20dioptre%20%3D%201%20%5C%20meter)
The object distance is
the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )
Generally the focal length is mathematically represented as
=>
=> ![f = 0.25 \ m](https://tex.z-dn.net/?f=f%20%3D%200.25%20%5C%20m)
converting to cm
=> ![f = 0.25 \ m = 0.25 * 100 = 25 \ cm](https://tex.z-dn.net/?f=f%20%3D%200.25%20%5C%20m%20%3D%200.25%20%2A%20100%20%3D%2025%20%5C%20cm)
Generally from lens equation we have that
![\frac{1}{f} +\frac{1}{v} -\frac{1}{u}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%2B%5Cfrac%7B1%7D%7Bv%7D%20-%5Cfrac%7B1%7D%7Bu%7D)
=> ![\frac{1}{25} +\frac{1}{v} -\frac{1}{-43}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B25%7D%20%2B%5Cfrac%7B1%7D%7Bv%7D%20-%5Cfrac%7B1%7D%7B-43%7D)
=> ![v = -15.8 \ cm](https://tex.z-dn.net/?f=v%20%3D%20%20-15.8%20%5C%20cm)
Generally the magnification is mathematically represented as
![m = \frac{v}{u}](https://tex.z-dn.net/?f=m%20%20%3D%20%5Cfrac%7Bv%7D%7Bu%7D)
=> ![m = \frac{- 15.8}{-43}](https://tex.z-dn.net/?f=m%20%20%3D%20%5Cfrac%7B-%2015.8%7D%7B-43%7D)
=> ![m = 0.3674](https://tex.z-dn.net/?f=m%20%20%3D%200.3674)