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3 years ago

A shell is fired with 500km/h on a target half kilometer away.In what time in which shell will hit the target.

Physics

1 answer:

Drupady [299]3 years ago

6 0

It depends on the direction in which the shell is launched. The time can be anything from 3.6 seconds to never.

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The weight of an object is measured in air to be 7.0 N. The

Vinil7 [7]

Answer:

Buoyant force = 3.0 N

The object will not float.

Explanation:

Apparent weight of a body immersed in water is the actual weight of object minus buoyant force

Given in the question that;

Weight of object in air = 7.0 N

Apparent weight of object = 4.0 N

4.0 N = 7.0 N - Buoyant force

Buoyant force = 7.0 - 4.0 = 3.0 N

In this case, the buoyant force is less than weight of the object thus the object will sink.

5 0

3 years ago

Explain newtons law of motion applied in this game

kirill [66]

Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

Newton’s third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction. This law is important in analyzing problems of static equilibrium, where all forces are balanced, but it also applies to bodies in uniform or accelerated motion.

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The first law represented in the game would be the candy. If you blow it, it would move but then stop due to friction.

The second law would be represented by blowing the candy. Since the candy was light, it would be easier to blow but if it was heavier, it would be a lot harder.

The final law represented in the game would be if you decided to blow the candy with a ballon instead, the candy would move the opposite direction the ballon is moving.

8 0

1 year ago

The Jensens dccided to spend their family vaeation white water rafting. During one segment of their trip down the river, the raf

torisob [31]

Answer:

24,187.04 J ≈ 24,200 J

Explanation:

mass (m) = 544 kg

initial speed (u) = 6.75 m/s

final speed (v) = 15.2 m/s

change in height (Δh) = -14 m (negative sign is because there is a decrease in height )

acceleration due to gravity (g) = 9.8 m/s^{2}

How much work was done on the raft by non conservative forces?

work done = change in energy of the system = change in kinetic energy + change in potential energy

work done = ( $0.5m(v^{2} -u^{2} )$ ) + (mgΔh)

work done = ( $0.5x544x(15.2^{2} -6.75^{2} )$ ) + (544 x 9.8 x (-14))

work done = 50449.76 - 74,636.8

work done = 24,187.04 J ≈ 24,200 J

7 0

3 years ago

answers At the beginning of 2019, Robotics Inc. acquired a manufacturing facility for $12.3 million. $9.3 million of the purchas

pshichka [43]

Answer:

$613,077

Explanation:

Calculation for the depreciation on the building for 2021

First step is to calculate the depreciation expense for the year 2019 and 2020 using this formula

Depreciation expense = (Purchase price - Residual value) ÷ (Useful life)

Let plug in the formula

Depreciation expense= ($9,300,000 - $1,300,000) ÷ (20 years)

Depreciation expense= ($8,000,000) ÷ (20 years)

Depreciation expense= $400,000

Second step is to calculate the book value for the year 2021 using this formula

Book value = Purchase price - Depreciation expenses *2 years

Let plug in the formula

Book value= $9,300,000 - $400,000 × 2

Book value= $8,500,000

Last step is to calculate the depreciation for 2021 using this formula

2021 Depreciation=(Book value-Residual value)÷Useful life

2021 Depreciation= ($8,500,000 - $530,000) ÷ (15 years - 2 years)

2021 Depreciation=$7,970,000÷13 years

2021 Depreciation= $613,077

Therefore the depreciation on the building for 2021 will be $613,077

8 0

3 years ago

How do you calculate distance using deceleration and time?

Effectus [21]

Answer:

U = initial velocity, t = time taken, s = distance covered. Deceleration Formula is used to calculate the deceleration of the given body in motion.

6 0

3 years ago