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vaieri [72.5K]
3 years ago
12

During which stage of the cell cycle does the cell condense chromosomes and break down the nuclear envelope? Group of answer cho

ices Anaphase Prophase Metaphase Telophase
Physics
1 answer:
Natalka [10]3 years ago
6 0

Answer:

Prophase

Explanation:

During the Prophase

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A 59.3 kg diver jumps off a board
ser-zykov [4K]

The board is 2.50m high.

Why?

We can calculate how high was the board applying the Law of Conservation of Mechanical Energy. This Law states that the mechanical energy (kinematic and potential) will be conserved during the motion.

It can be described with the following formula:

E_{M_{1}}=E_{M_{2}}\\\\PE_{1}+KE_{1}=PE_{2}+KE_{2}

PE=m*g*h\\KE=\frac{1}{2}m*v^{2}

At the top of the boar, the kinetic energy is equal to 0.

At the water, the potential energy is equal to 0.

So,

PE_{1}=KE_{2}\\\\m*g*h=1450J\\\\59.3kg*9.8\frac{m}{s^{2}}*h=1450J\\ \\h=\frac{1450J}{59.3kg*9.8\frac{m}{s^{2}}}=2.50m

Hence, we have that the board is 2.50m high.

Have a nice day!

6 0
4 years ago
Jon recently drove to visit his parents who live 648 miles away. On his way there his average speed was 14 miles per hour faster
Vladimir79 [104]

Answer:

speed of the Jon visiting parents = 56 mph

           speed of the Jon when returning from home = 56 - 14 = 42 mph

Explanation:

given,

distance of Jon parent's house = 648 mile

avg speed when he was visiting his parent's house be 'x' mph

avg speed when he is returning from his parent's house be 'x-14' mph

total time taken = 27 hours

total distance = speed × time

648 = x × t₁

t_1 = \dfrac{648}{x}

648 = ( x - 14 ) × t₂

t_2 = \dfrac{648}{x-14}

t = t₁ + t₂

27 = \dfrac{648}{x} + \dfrac{648}{x-14}

1 = 24 (\dfrac{1}{x} + \dfrac{1}{x-14})

x² - 62 x + 336 = 0

x² - 56 x - 6 x + 336 = 0

(x - 56 )(x - 6)=0

on solving

x = 56 ,6

hence, speed of the Jon visiting parents = 56 mph

           speed of the Jon when returning from home = 56 - 14 = 42 mph

8 0
3 years ago
Read 2 more answers
A 5.6 MeV (kinetic energy) proton enters a 0.39 T field, in a plane perpendicular to the field. What is the radius of its path?
Kisachek [45]

Answer:

the radius of the protons path is r = 0.85 m.

Explanation:

the force due to magnetic fields lead to the cetripetal force, such that:

F = q×v×B = m×(v^2)/r

         q×B = m×v/r

then:

r = m×v/q×B

r = p/q×B

then, the kinetic energy of the proton:

K = 1/2×m×v^2 = p^2/(2×m)

q×B = \sqrt{2×m×K}/r

    r =  \sqrt{2×m×K}/(q×B)

      =  \sqrt{2×(1.67×10^-27)×(5.3×1.60×10^-13)}/(1.60×10^-19×0.39)

      = 0.85 m  

7 0
4 years ago
A racetrack curve has radius 70.0 m and is banked at an angle of 12.0 ∘. The coefficient of static friction between the tires an
zubka84 [21]

Answer:

See attachment below

Explanation:

7 0
4 years ago
You are given two rectangular blocks of shiny metal, Block A and Block B, and are asked to determine which one will float in a b
vladimir2022 [97]

Answer:

Explanation:

Volume of block A = 10 x 6 x 1 = 60 cm³

Mass of block A = 630 g

density of mass A = mass / density

= 630 / 60 = 10.5g / cm³

Volume of block B = 5 x 5 x 3 = 75 cm³

Mass of block A = 604 g

density of mass A = mass / density

= 604 / 75 = 8.05 g / cm³

Since density of both A and B are less than that of mercury , both will float in mercury.

7 0
4 years ago
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