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Harrizon [31]
3 years ago
6

Dissolving continues until an equilibrium is established. O True O False

Chemistry
1 answer:
vazorg [7]3 years ago
7 0
Answer: It’s true

Explanation:
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What is the pH of a 2.0 x 10^-4 M solution of nitric acid (HNO3)
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Hello!

datos:

Molarity = 2.0*10^{-4}\:M\:(mol/L)


ps: The ionization constant of the nitric acid is strong (100% ionized in water) or completely dissociates in water, so the pH will be:

pH = - log\:[H_3O^+]

pH = - log\:[2*10^{-4}]

pH = 4 - log\:2

pH = 4 - 0.30

\boxed{\boxed{pH = 3.70}}\end{array}}\qquad\checkmark

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR!

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If a gas has a volume of 1000 ML at a temperature of 23°C and a pressure of 100 mmhg, what is it’s volume under standard conditi
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Answer:

119.7 mL.

Explanation:

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<em>PV = nRT.</em>

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

  • For the same no. of moles of the gas at two different (P, V, and T):

<em>P₁V₁/T₁ = P₂V₂/T₂.</em>

  • P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.
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<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂) </em>= (100.0 mmHg)(1000.0 mL)(273.0 K)/(296 K)(760.0 mmHg) =  121.4 <em>mL.</em>

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