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Zanzabum
3 years ago
12

Chemistry

Chemistry
1 answer:
postnew [5]3 years ago
7 0

There are 48.72 g  Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%

mass of Fluorine :

\tt 48.72\%\times 200=97.44~g

So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :

\tt =\dfrac{97.44}{2}=48.72~g

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I presume that you are using the comma as a decimal separator.

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