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3 years ago

- Which theory was the natural beginning of a Big Bang theory?

1 answer:

8 0

Well, the big bang theory was that the universe started to expand at and extrmly fast rate. We're talking several billion kilometers in less than a second. People think that our univers was pretty much shot out into space in a ciertain direction. During this, the univers has expanded and widen't to unimaginable size. but we really don't know what happend, and we may never find out. Who knows?

You might be interested in

Aluminum chloride can be formed from its elements:

saul85 [17]

<u>Answer:</u> The $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of $AlCl_3$ is:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)$ $\Delta H^o_{formation}=?$

The intermediate balanced chemical reaction are:

(1) $HCl(g)\rightarrow HCl(aq.)$ $\Delta H_1=-74.8kJ$ ( × 6)

(2) $H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$ $\Delta H_2=-185kJ$ ( × 3)

(3) $AlCl_3(aq.)\rightarrow AlCl_3(s)$ $\Delta H_3=+323kJ$ ( × 2)

(4) $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)$ $\Delta H_4=-1049kJ$

The expression for enthalpy of formation of $AlCl_3$ is,

$\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]$

Putting values in above equation, we get:

$\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ$

Hence, the $\Deltas H^o_{formation}$ for the reaction is -1406.8 kJ.

6 0

2 years ago

A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o

atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

$C(s)+O_{2}(g)\rightarrow CO_{2}(g)$

From the above balanced reaction, 1 mole of carbon releases 1 mole of $CO_{2}$ gas.

Converting mass of charcoal into moles as follows:

$n=\frac{m}{M}$

Molar mass of pure carbon is 12 g/mol thus,

$n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol$

The same moles of $CO_{2}$ is released. Converting these moles into mass as follows:

m=n×M

Molar mass of $CO_{2}$ is 44 g/mol thus,

$m=125mol\times 44 g/mol=5.5\times 10^{3}g$

Converting mass into kg,

$1g=10^{-3}kg$

Thus, total mass of gas released is 5.5 kg.

7 0

3 years ago

Relative mass each element contributes to the mass as a whole is _________.

Korolek [52]

Your a furry cause I don’t know

3 0

3 years ago

a) One kmol of N2O4 dissociates at 25℃, 1 atm to form an equilibrium ideal gas mixture of N2O4 and NO2 in which the amount of N2

horsena [70]

Answer:

neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C

Explanation:

ni change eq.

N2O4 1 1 - x 0.8154.....P = 1 atm; T = 25°C

NO2 0 0 + x x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))

⇒ x = neq = 0.0205 mol

⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol

3 0

3 years ago

In examining several amino acids, you want to identify the feature or features that differentiate one amino acid from another. W

sergiy2304 [10]

Your answer is C
amino acids are created by a bond of two carbon atoms and each carbon is part of a different group, one negative and one positive. when the chemical reactions occurs, it creates the several diff amino acids

4 0

3 years ago

Read 2 more answers