The first law of thermodynamics?

Two massive particles with identical charge are launched into the uniform field between two plates from the same launch point wi

Svetach [21]

<h2>Answernswe:</h2>

<h2>The interaction between charged object is a non-contact force that acts over some distance of separation.Charge,charge and distance.Every electrical interaction involves a force that highlights the importance of these three variables</h2>

er

6 0

3 years ago

What difference does a flat tire have against a good tire in starting a car to move?

marshall27 [118]

Answer: the flat fire the car cannot move correctly ,while in the good tire the car can move correctly

Explanation: because the flat tire will not allow the person to drive correctly, while the good tire is can allow a person to drive correctly.

6 0

3 years ago

9. The Metro Rail makes a stop at NRG Stadium to pick up some Texans fans after the game. After

attashe74 [19]

Answer:

It takes the train 7.5 seconds to reach top speed

The train travels 112.5 meters before it reaches its top speed

Explanation:

The Metro Rail makes a stop at NRG Stadium to pick up some Texans

fans after the game

After all the passengers board, the train accelerates at a rate of 4 m/s²

to a top speed of 30 m/s

We need to find the train takes how many seconds to reach the

top speed

Given is:

→ The train start from rest, then its initial speed u = 0

→ It acceleration a = 4 m/s²

→ Its top speed v = 30 m/s

To find the time we can use this rule;

→ $t=\frac{v-u}{a}$

→ $t=\frac{30-0}{4}=\frac{30}{4}=7.5$ seconds

It takes the train 7.5 seconds to reach top speed

Now we need to find how far the train travels before reaches top speed

We can use this rule;

→ v² = u² + 2as, where s is the distance

→ v = 30 m/s , u = 0 , a = 4 m/s²

Substitute these values in the rule

→ (30)² = 0 + 2(4) s

→ 900 = 8 s

Divide both sides by 8

→ s = 112.5 m

The train travels 112.5 meters before it reaches its top speed

7 0

3 years ago

A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow

Oksana_A [137]

Answer:

a) $\omega=1.36rad/s$

b) $\omega=12.99rpm$

c) $F=705.6N$

Explanation:

a) The angular velocity is related to the centripetal acceleration by the formula $a_{cp}=\omega^2r$ , which for our purposes we will write as:

$\omega=\sqrt{\frac{a_{cp}}{r}}$

Since we want this acceleration to be 1.5 times that due to gravity, for our values we will have:

$\omega=\sqrt{\frac{1.5g}{r}}=\sqrt{\frac{(1.5)(9.8m/s^2)}{(8m)}}=1.36rad/s$

b) 1 rpm (revolution per minute) is equivalent to an angle of $2\pi$ radians in 60 seconds:

$1\ rpm=\frac{2\pi rad}{60s} =\frac{\pi}{30}rad/s$

Which means we can use the conversion factor:

$\frac{1\ rpm}{\frac{\pi}{30}rad/s}=1$

So we have (multiplying by the conversion factor, which is 1, not affecting anything but transforming our units):

$\omega=1.36rad/s=1.36rad/s(\frac{1\ rpm}{\frac{\pi}{30}rad/s})=12.99rpm$

c) The centripetal force will be given by Newton's 2nd Law F=ma, so on the centripetal direction for our values we have:

$F=ma=(48kg)(1.5)(9.8m/s^2)=705.6N$

8 0

3 years ago

How would you define matter?

hoa [83]

Answer:

C

Explanation:

Searched up the answer.

5 0

3 years ago