<span>Which shapes are topologically equivalent to Choice 2? D. NONE
Choice 1, 3, and 4 are topologically equivalent. These figures each have two holes.
Choice 2 has three holes and is different from the other.
Topologically equivalent figures are figures that can be rearranged to form another shape without breaking.</span>
This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get
i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:
where 
is a compact way to indicate both solutions 
and 
, while 
are the coefficients of the quadratic equation, i.e. we consider the polynomial 
.
So, in your case, we have 
Plug those values into the formula to get
So, the two solutions are
The best and most correct answer among the choices provided by your question is none of the above.
<span>
The formula for π (pi) of the circle in terms of the circumference and radius is: Pi = C/2r.</span>
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If it is 5+2x=2x+6 than the answer is no solution
