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Ksenya-84 [330]
2 years ago
5

A set of weights includes a 4 lb barbell and 6 pairs of weight plates. Each pair of plates weighs 20 lb. If x pairs of plates ar

e added to the barbell, the total weight of the barbell and plates in pounds can be represented by f(x) = 20x + 4.
Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
3 0

Answer:

Range[4,24,44,64,84,104,124]

Step-by-step explanation:

CHECK THE COMPLETE QUESTION BELOW;

A set of weights includes a 4 lb barbell and 6 pairs of weight plates. Each pair of plates weighs

20 lb. If x pairs of plates are added to the barbell, the total weight of the barbell and plates in

pounds can be represented by f x( ) = 20x + 4.

What is the range of the function for this situation?

The range of a function can be defined as the difference between the maximum and minimum function. From the question, we can deduced that the minimum function of X is 0 and no plate is added, and the maximum is 6

The given function is

f(x) = 20x + 4 =

f(0) = 20(0) + 4

= 4

f(6) = 20(6) + 4

= 124

Which means the range is within 4 and 124.

But we are told from the question that Each pair of plates weighs 20 lb, which means there is difference of 20ib each between 4 and 24

Then we can compute the range as [4,124] or (4,24,44,64,84,104,124)

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Answer:

x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]

Step-by-step explanation:

you have the following formula:

(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1

To solve this equation you use the following properties:

log_aa^x=x

Thne, by using this propwerty in the equation (1) you obtain for x

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Answer:

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aleksandr82 [10.1K]

Answer:

11

Step-by-step explanation:

Evaluate using

PEMDAS

First we do what is inside of the Parenthesis 12 - 9 = 3

Now we have 2 + 3²

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there is no multiplication or division needed so we go straight to addition

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cluponka [151]

Answer:

158.76 cm²

Step-by-step explanation:

Quadrilateral ABCD is composed of 2 right triangles

Construct the line BD, then

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Δ ABD with b = 18 and h = 7.5

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