Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
First you need to distribute the exponent into the terms for the first parenthesis.
(-3x²y³)³ = (-3)³ * (x²)³ * (y³)³
= -27 *x⁶ *y⁹
= -27x⁶y⁹
Then you multiply -27x⁶y⁹ by x²y.
You just need to add the exponents of x and y:
-27x⁶⁺²y⁹⁺¹
= -27x⁸y¹⁰
Step-by-step explanation:
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Answer:
Step-by-step explanation:
<u>Given </u><u>:</u><u>-</u><u> </u>
- A quadratic equation is given to us.
- The equation is 2x² + 7x +6=0
And we need to find out the roots of the given equation. We can use the middle term splitting method to find out the roots as ,
<u>Given </u><u>equation</u><u> </u><u>:</u><u>-</u>
Step 1: <u>Find</u><u> out</u><u> the</u><u> </u><u>factors</u><u> </u><u>of </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>
We will choose the two factors such that their sum equals to the coefficient of x i.e. 7 .The factors are , 1×12 , 2×6 , 3×4 .
- And 3 + 4 = 7. So we will break the middle term into 3x and 4x .
Step 2 :<u> Breaking</u><u> the</u><u> </u><u>middle</u><u> term</u><u> </u><u>:</u><u>-</u><u> </u>
Step 3: <u>Take </u><u>out </u><u>common</u><u> </u><u>from </u><u>terms </u><u>:</u><u>-</u>
Step 4 : <u>Equate </u><u>them </u><u>with </u><u>0</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Hence </u><u>the</u><u> </u><u>correct</u><u> </u><u>options </u><u>are </u><u>C </u><u>and </u><u>D </u><u>.</u>