Which factor is least likely to limit the rate of photosynthesis?

Please help in this question!! I will mark brainlest

LUCKY_DIMON [66]

Answer:

im not too sure about that all i know is history

4 0

3 years ago

If the object represented by the FBD below has a mass of 2.5 kg, what is the acceleration of the object?

Debora [2.8K]

Answer:

4 m/s² down

Explanation:

We'll begin by calculating the net force acting on the object.

The net force acting on the object from the left and right side is zero because the same force is applied on both sides.

Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:

Force up (Fᵤ) = 15 N

Force down (Fₔ) = 25 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fᵤ

Fₙ = 25 – 15

Fₙ = 10 N down

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (ml= 2.5 Kg

Net force (Fₙ) = 10 N down

Acceleration (a) =?

Fₙ = ma

10 = 2.5 × a

Divide both side by 2.5

a = 10 / 2.5

a = 4 m/s² down

Therefore, the acceleration of the object is 4 m/s² down

6 0

3 years ago

The peak luminosity of a white dwarf supernova is around 1010 Lsun, and it remains brighter than 108 Lsun for about 150 days. In

Airida [17]

Answer:

Explanation: find the attached solution below

8 0

3 years ago

Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons a

dsp73

Answer:

$E=576.5V/m$

Explanation:

From the question we are told that:

Length $l=56.0cm=0.56m$

Distance apart $d=7.0mm=0.007m$

Electron Transferred $n=10^{-10}$

Therefore

Total Charge

Since Charge on each electron is

$e=1.602*10^{-19}$

Therefore

$T=1.602*10^{-19} *10^{10}$

$T=1.602*10^{-9}$

Generally the equation for Charge density is mathematically given by

$\rho=T/A$

Where

Area

$A=0.56*0.56$

$A=0.3136$

Therefore

$\rho=1.602*10^{-9}/0.3136$

$\rho=5.10*10^{-9}$

Generally the equation for Electric Field in the capacitor is mathematically given by

$E=\frac{\rho}{e_0}$

$E=\frac{5.10*10^{-9}}{8.85x10{-12}}$

$E=576.5V/m$

8 0

2 years ago

Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu

ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm ( $\lambda_{0} = 434nm$ , $\lambda_{0} = 410nm$ )

$Redshift: \lambda_{measured} > \lambda_{0}$

$Blueshift: \lambda_{measured} < \lambda_{0}$

Since, $\lambda_{measured}$ (444nm) is greater than $\lambda_{0}$ (434 nm) and $\lambda_{measured}$ (420nm) is greater than $\lambda_{0}$ (410 nm), it can be concluded that the star is moving away from the observer

6 0

3 years ago