Answer:t=0.54 s
Explanation:
Given
Jacob is traveling 5 m/s in North direction
Jacob throw a ball with a in south direction with a velocity of 5 m/s
Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0
Time taken by ball to reach ground
t=0.54 s
Motion of ball will be straight line
Height increase h = R*(1 - cosΘ) = 1.2*(1-cos3.5°) = .00224 m.
<span>½Mbl*Vbl² = Mbl*g*h → </span>
<span>Vbl = √(2gh) = .2095 m/s </span>
<span>This is the initial velocity of the block. From momentum considerations, </span>
<span>Mbt*Vbt = Mbl*Vbl → </span>
<span>Vbt = (Mbl/Mbt)*Vbl = (5/.002)*.2095 = 523.8 m/s
this is what i think the answer is im not for sure though... hope it helps...</span>
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Work = 25N x 4 meters = 100 J
Answer:
The period of 6/7 seconds or 0.857 seconds.
Explanation:
The period of any given trigonometric function is given by:
In this function b is
So, the period for the given function is calculated as follows: