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Aleonysh [2.5K]
3 years ago
15

SPHERE VOLUME What is the exact volume of a sphere that has a radius of 8.4 in.?

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0
V = 4/3 * pi * r^3

V = 4/3 * pi * 8.4^3

Simplify exponent:

V = 4/3 * pi * 592.704

Multiply:

V = 790.272pi
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* Required
Furkat [3]
B. 19.8

Use the Pythagorean theorem:
14.2^ + x^ = 24.4^
201.64 + x^ = 595.36
x^ = 393.72
x = 19.84
8 0
3 years ago
Two storage sheds are to have the same area. One is square and one is rectangular. The rectangular shed is 4 meters wide and 9 m
aliina [53]
Area is calculated by taking the length times the width.
A=lxw

one shed is 9 x 4 =36 square feet.
the other shed will be the same but have a four sides equal.
a shed with side of 6 x 6 will have a area of 36 square feet.

one side of the square shed would be 6 feet.

brainliest is always appreciated..
6 0
3 years ago
Can someone show me hwo to do this so that i know how to do this please
spin [16.1K]

Answer:

y = -2x - 2

Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
Please brake down why !
lana66690 [7]

Answer:

D

Step-by-step explanation:

using the rule of radicals

• \sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

simplifying \sqrt{32}

\sqrt{32} = \sqrt{16(2)} = \sqrt{16} × \sqrt{2} = 4\sqrt{2}

\sqrt{32} + 5\sqrt{2}

= 4\sqrt{2} + 5\sqrt{2} = 9\sqrt{2} → D



4 0
3 years ago
Fish story: According to a report by the U.S. Fish and Wildlife Service, the mean length of six-year-old rainbow trout in the Ar
Yanka [14]

Answer:

11.29.

Step-by-step explanation:

We are given that The mean length of six-year-old rainbow trout in the Arolik River in Alaska is 478 millimeters with a standard deviation of 38 millimeters.

We are also given that these lengths are normally distributed.

So, The highest value is at mean .(Refer the attached figure).

Formula : Percentile = \frac{Length}{Maximum} \times 100

54 = \frac{Length}{478} \times 100

\frac{5400}{478} =Length

11.297 =Length

The 54th percentile of the lengths is 11.29.

4 0
3 years ago
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