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Tresset [83]
3 years ago
12

What is the net force of 4N 2N!!

Chemistry
1 answer:
RSB [31]3 years ago
8 0

Answer: 4 N-2 N=2 Nto the left. Change in motion: The box will move to the left. 7.)

Explanation: Please mark branliest.

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What is the daughter nuclide when 0-15 experiences positron emission?
Helen [10]

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles γ
  • positron particles ₁e⁰

O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

 \tt _8^{15}O\Rightarrow _7^{15}N+_1^0e

The mass number of the daughter isotope = 15, atomic number = 7

If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)

5 0
3 years ago
Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ
Mademuasel [1]

Answer:

\boxed{-6.29 \times10^{5}\text{ J}}

Explanation:

Step 1. Determine the cell potential

                                                  <u>    E°/V     </u>

2×[Cr ⟶ Cr³⁺ + 3e⁻]                  0.744  V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu]             </u>   <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu  + 2Cr³⁺    1.086  V

Step 2. Calculate ΔG°

\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}

6 0
3 years ago
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