Answer:
B: Increasing the volume inside the reaction chamber
Explanation:
Answer:
Oxygen's atomic weight is 16.00 amu. 1 mole of oxygen is 6.02 x 1023 atoms of oxygen 1 amu = 1.661 x 10-24g What is the molar mass (g/mole) of oxygen? Molar mass (in grams) is always equal to the atomic weight of the atom! Molar mass (in grams) is always equal to the atomic weight of the atom!
Answer:
C₂H₈N₄O₆ is the molecular formula for the compound
Explanation:
Data from the problem:
13 g of C in 100 g of compound
4.3 g of H in 100 g of compound
30.4 g of N in 100 g of compound
52.2 g of O in 100 g of compound
Firstly we determine, the mass of each in 184 g of compound, which is 1 mol
(13 g / 100 g) . 184 g = 24 g C
(4.3 g / 100 g) . 184 g = 7.91 g H ≅ 8 g H
(30.4 g / 100 g) . 184 g = 56 g N
(52.2 g / 100 g) . 184 g = 96 g O
And now, we divide the mass by the molar mass of each to determine the moles:
24 g C / 12 g/mol = 2 mol C
8g H / 1 g/mol = 8 mol H
56 g N / 14 g/mol = 4 mol N
96 g O / 16 g/mol = 6 mol O
So the molecular formula of the compound is C₂H₈N₄O₆
Answer:
Explanation:
Given parameters:
Molarity of KOH = 0.26M
Volume of H₂SO₄ = 19.76mL
Molarity of H₂SO₄ = 0.20M
Unknown:
Volume of KOH = ?
Solution:
This is a neutralization reaction in which an acid reacts with a base to produce salt and water:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
We solve from the known to the unknown in the reaction.
The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:
Number of moles of acid = molarity x volume
Number of moles of acid = 19.76 x 0.20 = 3.95mol
From the balanced reaction equation:
1 mole of acid reacts with 2 moles of the bases KOH
3.95mole of acid would react with 3.95moles x 2 of the base
Number of moles of reacting base = 7.90moles
To find the volume of base;
Volume of base = 
Volume =
= 30.40mL
Learn more:
Neutralization brainly.com/question/6447527
#learnwithBrainly
Answer:
The Answer is gonna be behavior that is simple, untaught, and born knowing:3
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