Answer:
The probability density (ψ2)
Explanation:
Indicates the probability of finding the electron in a certain region of space when it is squared ψ2.
This means that define2 defines the distribution of electronic density around the nucleus in three-dimensional space; a high density represents a high probability of locating the electron and vice versa.
The atomic orbital, can be considered as the electron wave function of an atom.
APPLICATIONS:
1.- Specify the possible energy states that the electron of the hydrogen atom can occupy and identify the corresponding wave functions medio, by means of a set of quantum numbers, with which an understandable model of the hydrogen atom can be constructed.
2.- It does not work for atoms that have more than one electron, but the problem is solved using approximation methods for polyelectronic atoms.
A two in both of the blanks will balence the equation. It will look like so:
2PbS(s) + 2O2(g) --> 2PbO(s) +2SO2(g)
Answer:
5.52atm
Explanation:
Using the pressure law formula:
P1/T1 = P2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the question, the following information were provided;
P1 = 4.72 atm
P2 = ?
T1 = -3.50°C = -3.50 + 273 = 269.5K
T2 = 42°C = 42 + 273 = 315K
Using P1/T1 = P2/T2
4.72/269.5 = P2/315
CROSS MULTIPLY
4.72 × 315 = 269.5 × P2
1,486.8 = 269.5P2
P2 = 1,486.8 ÷ 269.5
P2 = 5.52atm
The reactants are found on the left side, the products are found on the right side.
Answer:
The molar mass of the gas is 44 g/mol
Explanation:
It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:
If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):
6,61 = √M₂
44g/mol = M₂
<em>The molar mass of the gas is 44 g/mol</em>
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I hope it helps!
