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lutik1710 [3]
3 years ago
7

Which organism has the following characteristics: heterotrophic, eukaryotic,

Chemistry
1 answer:
Soloha48 [4]3 years ago
6 0

This organism is Fungi, which can either be unicellular or multicellular, and has the only cell wall made of chitin out of the four.

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What mass of cu(s) is electroplated by running 26.5 a of current through a cu2+(aq) solution for 4.00 h?
kramer
T = 14400 s 
26.5 x 14400=381600 C 
381600/96500=3.95 Faradays 
Cu2+ + 2e- = Cu 
3.95 faradays ( 1 mol/ 2 Faradays) = 1.97
mass = 1.97 x 63.55 g/mol=125 g 

moles Au = 33.1 / 196.967 g/mol=0.168 
Au+ + 1e- = Au 
0.168 ( 1 Faraday/ 1mol)= 0.168 Faraday 
0.168 x 96500=16217 Coulombs 
16217 / 5.00=3243 s => 54 min
7 0
3 years ago
Is the equation balanced? Why or why not?
anygoal [31]

Answer:

Yes because the law of conservation of matter is followed. There are equal numbers of atoms of all elements in the

reactants and products.​

Explanation:

A balanced equation conform to the law of conservation of matter. While unbalanced equation suggests that matter has been created or destroyed.

Na3PO4 + 3KOH —> 3NaOH + K3PO4

A careful observation of the above equation proved that the equation is balanced is balanced because there are equal numbers of atoms of all elements in the

reactants and products.

8 0
4 years ago
Need help on this really bad!
timofeeve [1]

Answer:

Help your self

Explanation:

7 0
2 years ago
Number of grams of hydrogen than can be prepared from 6.80g of aluminum​
Anastaziya [24]

Answer:

0.7561 g.

Explanation:

  • The hydrogen than can be prepared from Al according to the balanced equation:

<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>

It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.

  • Firstly, we need to calculate the no. of moles of (6.8 g) of Al:

no. of moles of Al = mass/atomic mass = (6.8 g)/(26.98 g/mol) = 0.252 mol.

<em>Using cross multiplication:</em>

2.0 mol of Al produce → 3.0 mol of H₂, from stichiometry.

0.252 mol of Al need to react → ??? mol of H₂.

∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.

  • Now, we can get the mass of H₂ that can be prepared from 6.80 g of aluminum:

mass of H₂ = (no. of moles)(molar mass) = (0.3781 mol)(2.0 g/mol) = 0.7561 g.

5 0
4 years ago
Which of the following elements ia an alkali metal?
Anna11 [10]

A) Potassium

Potassium contains the six chemical elements that make it an alkali metal?

7 0
3 years ago
Read 2 more answers
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