Something that goes round in circles could have a high speed but zero average velocity.
Answer:
0.56 km/s
Explanation:
We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.
![560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s]](https://tex.z-dn.net/?f=560%5B%5Cfrac%7Bcm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%3D5.6%5Bm%2Fs%5D%5C%5C0.56%5B%5Cfrac%7Bkm%7D%7Bs%7D%5D%2A%28%5Cfrac%7B1000m%7D%7B1km%7D%20%29%3D560%5Bm%2Fs%5D)
Therefore the speed of 0.56 [km/s] is the greatest of all
6mph:
Suppose the boat is traveling on a y axis. The river flow acts on the x axis. Motion on each axes are independent. The linear speed of the boat is not changed. Furthermore the projectile motion is changing, but you're specifically asking about the linear speed of the boat which is unchanged.
Answer:
35%
Explanation:
Given data
Amount of energy transferred (Input) = 270J
Amount of energy converted to sound (Output)= 94.5J
Efficiency = output/input*100
Efficiency= 94.5/270*100
Efficiency=0.35*100
Efficiency=35%
Hence the efficiency is 35%
Answer:
The source is at a distance of 4.56 m from the first point.
Solution:
As per the question:
Separation distance between the points, d = 11.0 m
Sound level at the first point, L = 66.40 dB
Sound level at the second point, L'= 55.74 dB
Now,

where

I = Intensity of sound
Now,

Similarly,

Now,




Solving the above quadratic eqn, we get:
R = 4.56 m