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Akimi4 [234]
3 years ago
12

I need help this is due today GIVING BRAINLIEST IM DESPERATE!

Physics
1 answer:
Nitella [24]3 years ago
3 0

Answer:

1: is A

2: is C

Explanation:

1: because all other option would imply that the truck was not moved from from its previous position due to the lack of work / force exerted by the car

2: this is because the less dense ball will have less opposing force action on it causing it to move / accelerate / go at a faster speed

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A plane flies at 400 north of East for 150 miles,then flies 200 miles at an angle of 150 west of North. What is the plane's fina
ivanzaharov [21]

Answer:

341.46miles

Explanation:

Find the diagram attachment.

To get the displacement D, we will use the cosine rule as shown;

D² = 200²+150²-2(160)(400)cos65°

D² = 40000+22500-128000cos65°

D² = 62500+54095.14

D² = 116595.14

D = √116595.14

D= 341.46 miles

Hence the plane final displacement is 341.46miles

3 0
2 years ago
What year did Badminton become a full-medal Olympic sport?
Basile [38]

Answer:

1992

Explanation:

Badminton made its debut as a demonstration sport at the 1972 Olympic Games in Munich. It was not until the 1992 Games in Barcelona that it was officially included on the Olympic programme, with men's and women's singles and doubles events.

6 0
3 years ago
While flying over the grand canyon the pilot
Veronika [31]
We cannot answer the question if we do not have the answers - sorry!!
6 0
3 years ago
A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera
Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
What is 3,278,000 as scientific notation?
jonny [76]
3.278*10^6 I think. Sorry if it’s wrong.
4 0
2 years ago
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