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m_a_m_a [10]
3 years ago
8

Dfine chemical reaction​

Chemistry
1 answer:
allsm [11]3 years ago
4 0

Answer:

A process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

Explanation:

Pretty much just not a physical reaction or otherwise

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vladimir1956 [14]
Delta energy on labelled diagram is attached below

4 0
3 years ago
19. I accidentally mixed bleach and ammonia when cleaning one day. It released 55 liters of deadly chlorine (CI) gas. How many g
user100 [1]
55,000 grams
Hope this helps you out :)
3 0
3 years ago
Write an equation for the neutralization of lemon juice with baking soda. Your equation should show a proton transfer to form ca
Jobisdone [24]

The equation of the neutralization reaction is:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

<h3>What is the acid in lemon juice?</h3>

The main acid in lemon juice is citric acid.

Citric acid is a tricarboxylic acid and will react with baking soda to form a salt and water.

The equation of the neutralization reaction is shown below:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

In conclusion, the neutralization of citric acid in lemon juice produces a salt and water.

Learn more about neutralization reaction at: brainly.com/question/15042730
#SPJ1

8 0
2 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.
DIA [1.3K]

Answer:

Q = 31798.4J = 31.79kJ

Explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ

6 0
3 years ago
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