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Tamiku [17]
3 years ago
15

Estimate the boiling point of water at a pressure of 1.1 atmosphere

Physics
1 answer:
Nezavi [6.7K]3 years ago
4 0
It is about 100oC at a pressure of 1.1 atmosphere. Hope this helps.
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A mango is dropped and fall freely from rest. What are its position and velocity after 1.0secs,2.0secs,and 3.0secs
irakobra [83]

Answer:

sxsdfsd

Explanation:

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Why do most coastal regions have two high tides and two low tides?
Dovator [93]
Because the Earth rotates through two tidal bulges every lunar day.
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What is the magnitude of the electric force between a proton and an electron when they are at a distance of 4.09 angstrom from e
Zinaida [17]

Answer:

F=1.38*10^{-9}N

Explanation:

According to Coulomb's law, the magnitude of the electric force between two point charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

F=\frac{kq_1q_2}{d^2}

Here k is the Coulomb constant. In this case, we have q_1=-e, q_2=e and d=4.09*10^-10m. Replacing the values:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)(1.6*10^{-19}C)}{(4.09*10^{-10})^2}\\F=-1.38*10^{-9}N

The negative sign indicates that it is an attractive force. So, the magnitude of the electric force is:

F=1.38*10^{-9}N

5 0
3 years ago
Fred is conducting a controlled experiment to test whether using a grow light at night will help a tomato plant grow faster. Bel
PtichkaEL [24]

Answer:

the type of tomato plants used.

Explanation:

4 0
3 years ago
A boat, whose speed in still water is 2.50 m/s, must cross a 285-m wide river and arrive at a point 118m upstream from where it
son4ous [18]

The figure shows the arrangement of system

The velocity of boat can be resolved in to two

     Horizontal component  = vcos θ = 2.50 cos 45 = 1.768 m/s

     Vertical component  = vsin θ = 2.50 sin 45 = 1.768 m/s

   Due to horizontal component the boat arrive arrives upstream,

           Total horizontal velocity =  1.768 - Vr, where Vr is the velocity of river.

  Total time taken to cross the river = width of river/ Vertical component of velocity

                         t = 285/1.768 = 161.20 seconds

So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds

That is           118 = (1.768-Vr)*161.20

                     1.768 - Vr =0.732

                         Vr = 1.036 m/s

So velocity of river flow =1.036 m/s

4 0
3 years ago
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