Estimate the boiling point of water at a pressure of 1.1 atmosphere

Cutting down the forest reduces the size of animal habitats, increases erosion, and results in an increase in the amount of carb

Julli [10]

Answer: D. plant more trees where forests are cut down.

Explanation:

Deforestation has to do with the cutting down of trees. Cutting down the forest reduces the size of animal habitats, increases erosion, and results in an increase in the amount of carbon dioxide in the atmosphere.

Ok order to tackle the above, it is necessary that we should plant more trees where forests are cut down.

6 0

2 years ago

PLZZ HELP???

Tanzania [10]

They bond basically

8 0

3 years ago

What volume of .2500 m cobalt iii chloride is required to react completely with 25 ml of .0315 m calcium hydroxide?

Lynna [10]

<span>f 0.0315 M calcium hydroxide?<span>Co2(SO4)3 + 3Ca(OH)2---> 2Co(OH)3+ 3CaSO4 Co Sulfate and Ca hydroxide react

could you mark as brailiest</span></span>

8 0

3 years ago

An ore sample weighs 17.50 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in

valkas [14]

Answer:

Volume of the sample: approximately $\rm 0.6422 \; L = 6.422 \times 10^{-4} \; m^{3}$ .

Average density of the sample: approximately $\rm 2.77\; g \cdot cm^{3} = 2.778 \times 10^{3}\; kg \cdot m^{3}$ .

Assumption:

$\rm g = 9.81\; N \cdot kg^{-1}$ .
$\rho(\text{water}) = \rm 1.000\times 10^{3}\; kg \cdot m^{-3}$ .
Volume of the cord is negligible.

Explanation:

<h3>Total volume of the sample</h3>

The size of the buoyant force is equal to $\rm 17.50 - 11.20 = 6.30\; N$ .

That's also equal to the weight (weight, $m \cdot g$ ) of water that the object displaces. To find the mass of water displaced from its weight, divide weight with $g$ .

$\displaystyle m = \frac{m\cdot g}{g} = \rm \frac{6.30\; N}{9.81\; N \cdot kg^{-1}} \approx 0.642\; kg$ .

Assume that the density of water is $\rho(\text{water}) = \rm 1.000\times 10^{3}\; kg \cdot m^{-3}$ . To the volume of water displaced from its mass, divide mass with density $\rho(\text{water})$ .

$\displaystyle V(\text{water displaced}) = \frac{m}{\rho} = \rm \frac{0.642\; kg}{1.000\times 10^{3}\; kg \cdot m^{-3}} \approx 6.42201 \times 10^{-4}\; m^{3}$ .

Assume that the volume of the cord is negligible. Since the sample is fully-immersed in water, its volume should be the same as the volume of water it displaces.

$V(\text{sample}) = V(\text{water displaced}) \approx \rm 6.422\times 10^{-4}\; m^{3}$ .

<h3>Average Density of the sample</h3>

Average density is equal to mass over volume.

To find the mass of the sample from its weight, divide with $g$ .

$\displaystyle m = \frac{m \cdot g}{g} = \rm \frac{17.50\; N}{9.81\; N \cdot kg^{-1}} \approx 1.78389 \; kg$ .

The volume of the sample is found in the previous part.

Divide mass with volume to find the average density.

$\displaystyle \rho(\text{sample, average}) = \frac{m}{V} = \rm \frac{1.78389\; kg}{6.42201 \times 10^{-4}\; m^{3}} \approx 2.778\; kg \cdot m^{-3}$ .

3 0

3 years ago

A football player is running with a velocity or 10 m/s. At that velocity, his momentum is 2500 kg*m/s. What is the football play

DedPeter [7]

The mass of the football player is 250 kg.

<u>Explanation:</u>

Momentum is defined as the product of mass and velocity. So here the velocity (v) is given as 10 m/s and the momentum is given as 2500 kg m /s. So we can determine the mass (m) of the player by substituting the known terms in the formula of determining momentum as shown below.

$\text {Momentum}(p)=m \times v$

As we know the value of momentum and velocity, the mass can be found as,

$m=\frac{p}{v}=\frac{2500}{10}=250 \mathrm{kg}$

Thus, the mass of the football player is found to be 250 kg.

7 0

2 years ago