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Sav [38]
4 years ago
7

_________ is a process in which water moves through a membrane

Physics
1 answer:
Nookie1986 [14]4 years ago
6 0

Answer:

osmosis

Explanation:

osmosis is the movement of solvent materials through a semi permeable membrane into a region of solute concentration, therefore water moving through a membrane is an osmotic process.

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A uniform meter stick (with a length of 1.00 meter) has a mass of 108 g. It is supported at its midpoint by a vertical rigid blu
alexandr1967 [171]

Answer:4

Explanation:

Given

m_1=21\ gm

m_2=27\ gm

Mass of stick is m=108\ gm

Let T be the tension in the red string

Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut

Therefore

T=m_1g+m_2g

T=(0.021+0.027)\times 10

T=0.48\ N

4 0
4 years ago
Which property increases as an electromagnetic waves energy decreases
Rufina [12.5K]

Answer:

Wavelength

Explanation:

3 0
3 years ago
Read 2 more answers
How the properties of sound waves change as they spread out in a spherical pattern
Vlad1618 [11]
It is when the air hit the wave and it moves to another direction.
6 0
3 years ago
A body is moving with velocity 30 m pr sec Wt will b the distance covered by a body in 1 sec??
madam [21]

Answer:

30 metres

Explanation:

The velocity is 30m/s and the time is one second.

Distance =Velocity×time..

Distance=30m/s×1 second

=30×1

=30 metres

6 0
3 years ago
Two parallel-plate capacitors, identical except that one has twice the plate separation of the other, are charged by the same vo
erik [133]

Answer:

The capacitor having less distance of separation has a stronger electric field.

Explanation:

The capacitors are identical and only difference between them is that one has twice the plate separation of the other. Therefore, capacitance of the given capacitors C1 and C2 is,

C1= Aε/d  and C2=Aε/2d

The charges Q1 and Q2 on the capacitors of capacitance C1 and C2 respectively, is then given by the equation,

Q1=VC1

Q1=VAε/d

Q2=VC2

Q2=VAε/2d

Therefore, the surface charge density σ1 and σ2 for the capacitors is,

σ1=Q1/A

σ1=VAε/(d*A)

σ1=Vε/d

Similarly,

σ2=Q2/A

σ2=Vε/2d

The electric field between the plates is directly proportional to the surface charge density. And so electric field is inversely proportional to the distance of separation. Therefore the capacitor whose distance of separation is less has a stronger electric field.

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8 0
3 years ago
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