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Svetlanka [38]
3 years ago
15

160 mL of a 37.5 % (m/v) LiNO3 solution

Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

60g of LiNO3 are required

Explanation:

<em>Calculate the amount of solute, in grams or milliliters, to prepare...</em>

<em />

The percentage mass/volume %(m/v) is defined as the mass in grams of the solute in 100mL of solution

To solve this question we must know that in a 37.5% (m/v) of LiNO3 you have 37.5g of LiNO3 in 100mL of solution.

Thus, to prepare 160mL are required:

160mL * (37.5g / 100mL) =

<h3>60g of LiNO3 are required</h3>
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