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Gelneren [198K]
4 years ago
6

Cu(NO3)2 + Na2CO3 → CuCO3 + 2NaNO3

Chemistry
1 answer:
Salsk061 [2.6K]4 years ago
6 0

Explanation:

Es tut mir nicht so leid

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Glucose and Oxygen
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A granola bar states that it is 17.0% protein; each granola bar has a mass of 35.0 grams. How many granola bars would you need t
FromTheMoon [43]

A granola bar states that it is 17.0% protein; each granola bar has a mass of 35.0 grams 5 bars need to consume to eat 29.7 grams of protein.

<h3 /><h3>What is protein?</h3>

Protein is a source of energy by which all humans and animals can do their work as it provide energy to the cells of the human and animal and important too.

A granola bar is source of protein contain 17.0% protein 35.0 grams each bar contain 5.2 gram protein 29.7 grams protein is in 5 bars of granola bar.

Therefore, granola bar states that it is 17.0% protein,each granola bar has a mass of 35.0 grams 5 bars need to consume to eat 29.7 grams of protein.

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5 0
2 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
Write the chemical formula of baking soda ?​
Fantom [35]

Answer:

NaHCO₃

Explanation:

NaHCO₃ is the chemical formula for sodium bicarbonate or baking soda. It has one sodium atom, one hydrogen atom, one carbon atom, and three oxygen atoms.

Have a good day and stay safe!

6 0
4 years ago
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