Answer:
84.0 ppm is the concentration of Red 40 dy in the original sports drink.
Explanation:
Concentration of red dye in sport drink before dilution 
Volume of the sport drink before dilution 
Concentration of red dye in sport drink after dilution 
Volume of the sport drink after dilution 
( dilution )
84.0 ppm is the concentration of Red 40 dy in the original sports drink.
Quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution is 3.
Antifreeze solution is a solute that lowers the freezing point of the liquid in a solution.
For calculating the amount of quarts of pure antifreeze solution added can be given by:
5×20/100 + x × 100% = (x+5) × 50/100
Where, x is the amount of antifreeze required for addition and pure antifreeze is 100% of the antifreeze taken.
1 + x = (x+5) 0.5
1 + x = 0.5x + 2.5
0.5x = 1.5
x = 3
So, 3 quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution.
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Answer:
i.e. mass of 1 mole of glucose, C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g.
His the answer I hope it helps
Answer:
Na
Explanation:
The atomic number of sodium is 11 while that of fluorine is 9 . Thus the number of electrons in sodium are 11 while in fluorine are 9 .
The cation of an atom form when atom lose electron.
Na → Na⁺ + e⁻
it means the cation of sodium loses its one outer most electron. Thus it has 10 electron while Na atom has 11 electron.
On other hand fluorine has 9 electrons.
The anion of an atom form when it gain electron.
F + e⁻ → F⁻
Thus the number of electrons in given species are,
Na = 11
Na⁺ = 10
F = 9
F⁻ = 10
Na has more number of electrons.
