Answer:
6.0 m/s vertical and 9.0 m/s horizontal
Explanation:
For the vertical component, we use the formula:
- Sin(34°) = <em>y</em> / 10.8
Then we <u>solve for </u><u><em>y</em></u>:
- 0.559 = <em>y</em> / 10.8
And for the horizontal component, we use the formula:
- Cos(34°) = <em>x</em> / 10.8
Then we <u>solve for </u><u><em>x</em></u><u>:</u>
- 0.829 = <em>x</em> / 10.8
So the answer is " 6.0 m/s vertical and 9.0 m/s horizontal".
B
Assume north and east as two sides of a right angled triangle. magnitude of the distance is then given by the length of the hypotenuse which is 
where a = 1.2 km north
and b = 1.6 km east
magnitude = 2 km
Direction is given by the angle between them, that is atan(a/b) = 36.86 deg north of east = 53.1 deg east of north.
Explanation:
Given that,
Initial speed of the sports car, u = 80 km/h = 22.22 m/s
Final speed of the runner, v = 0
Distance covered by the sports car, d = 80 km = 80000 m
Let a is the acceleration of the sports car. It can be calculated using third equation of motion as :




Value of g, 


Hence, this is required solution.
Answer:
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