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lukranit [14]
2 years ago
13

Does a force need to force itself to force a force to force itself?​

Physics
1 answer:
Leno4ka [110]2 years ago
4 0

Answer:

<em><u>Yes</u></em><em><u>.</u></em>

Explanation:

Force can force anything or even force itself to force something.

Also, force is an energy, so it can force anything, push anything, etc.

You might be interested in
100 meters toward the shore in 25 seconds
Rzqust [24]

Answer:

The speed of a turtle is 4m/s

Explanation:

speed = distance/time

distance = 100m

time = 25s

s = 100/25

= 4m/s

6 0
3 years ago
The equatorial diameter of earth is 7928 miles. If a mile equals 1.609 km, what is the earth's diameter in kilometers? in centim
tangare [24]

diameter of earth in miles= 7928 miles

1 mile = 1.609 km

diameter of earth in km= 7928*1.609

                                         =12,756.152 km

Hope it helped u, pls thank if u find this helpful

and don't forget to put this answer as the brainliest.

^_^.

7 0
2 years ago
An object has a kinetic energy of 275 j and the momentum of magnitude of 25.0 kg m/s. find the speed and mass of the object
lyudmila [28]
<span>Recall formula for Kinetic energy is: KE = 1/2mv^2, where KE = 275J and momentum (which is 25.0 kg m/s) = m*v Therefore substitute for KE and mv in the equation above to get speed => 275 = 0.5 * 25 * v v = 275/12.5 v = 22m/s to get mass m, recall momentum = m*v => 25= 22*m m= 25/22 = 1.3663kg</span>
6 0
3 years ago
A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8
Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

\eta =1-\frac{T_c}{T_h}

where,

\eta = efficiency = 0.780

T_h = Temperature of hot reservoir = ?

T_c = Temperature of cold reservoir = -24.8^oC=273+(-24.8)=248.2K

Now put all the given values in the above expression, we get:

\eta =1-\frac{T_c}{T_h}

0.780=1-\frac{248.2K}{T_h}

T_h=1128.18K

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0
3 years ago
A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal in
erica [24]

Explanation:

Given that,

Mass of a freight car, m_1=30,000-kg

Speed of a freight car, u_1=0.85\ m/s

Mass of a scrap metal, m_2=110,000\ kg

(a) Let us assume that the final velocity of the loaded freight car is V. The momentum of the system will remain conserved as follows :

30000\times 0.85=(30000+110000)V\\\\V=\dfrac{30000\times 0.85}{30000+110000}\\\\=0.182\ m/s

So, the final velocity of the loaded freight car is 0.182 m/s.

(b) Lost on kinetic energy = final kinetic energy - initial kinetic energy

\Delta K=\dfrac{1}{2}[(m_1+m_2)V^2-m_1u_1^2)]\\\\=\dfrac{1}{2}\times [(30,000+110,000 )0.182^2-30000(0.85)^2]\\\\=-8518.82\ J

Lost in kinetic energy is 8518.82. Negative sign shows loss.

6 0
2 years ago
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