Answer:
work accomplished = 300*30
= 9,000 J
applied work = 9,000 + 2,000 = 11,000 Joules
efficiency = 100 * work accomplished/work applied
= (9/11)100 = 81.8 %
force applied = (300/6)/.818
= 61.1 N
assuming that the 6 in your question refers to mechanical advantage
Answer:
The track's angular velocity is W2 = 4.15 in rpm
Explanation:
Momentum angular can be find
I = m*r^2
P = I*W
So to use the conservation
P1 + P2 = 0
I1*W1 + I2*W2 = 0
Solve to w2 to find the angular velocity
0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2
W2 = 0.435 rad/s
W2 = 4.15 rpm
Answer:
1752.14 tonnes per year.
Explanation:
To solve this exercise it is necessary to apply the concepts related to power consumption and power production.
By conservation of energy we know that:
Where,
Production of Power
Consumption of power
Where the production of power would be,
Where,
m = Total mass required
Energy per Kilogram
Efficiency
The problem gives us the aforementioned values under a production efficiency of 45%, that is,
Replacing the values we have,
Solving for m,
We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,
tonnes per year.
Answer:
Explanation:
Partial Variation is a relation that is of the form y = mx+b. The graph of y = mx+b is a straight line with the slope of m and a y-intercept of b. ... The relation y = mx +b represents partial variation because the value of y varies partially with the value of x.
A displacement time graph is able to show if an object is going backwards or forwards for example usually a line with a negative gradient means going backwards (or back to the start) This CAN’T be shown on a distance time graph
A distance time graph shows how far an object has traveled in a given time
So for example...
Distance is plotted on the Y-axis
Time is plotted on the X-axis
So not they are not the same, hope this helped :)
