Identify the scale of measurement used.

Small blocks A and B are held at rest on a smooth plane inclined at 30° to the horizontal. Each is held in equilibrium by a forc

Olin [163]

<h3>Answer :</h3>

First of all, See the attachment for better understanding $.$

_________________________________

❂ Weight of block A :

➝ mg sin30° = 18

➝ W (1/2) = 18

➝ W = 18×2

➝ W = 36N 

❂ Weight of block B :

➝ N sin30° = 18

➝ (Mg cos30°) sin30° = 18

➝ W' (√3/2)(1/2) = 18

➝ W' (√3/4) = 18

➝ W' = 72/√3

➝ W' = 41.61N

5 0

3 years ago

Dr. Lopez is Thomas's doctor. During his appointment, Thomas says he thinks

alukav5142 [94]

A. Conduct an exam. Thomas might have a drug dependence.

(Please mark Brainliest! :D)

8 0

3 years ago

People are good at learning to recognize _______________. *

suter [353]

Answer:

A

Explanation:

7 0

3 years ago

Read 2 more answers

What do you mean by force?

salantis [7]

It’s to push an object in it’s direction of where it’s leading to.

3 0

3 years ago

Introduction: The specific heat capacity of a substance is the amount of energy needed to change the temperature of that substan

ki77a [65]

Answer:

A) 8,368 J

B) ) 0.893 J/gºC

Explanation:

A)

The heat gained by the water can be obtained solving the following equation:

$q_{g} = c_{w} * m * \Delta T (1)$

where cw = specific heat of water = 4.184 J/gºC
m= mass of water = 1,000 g
ΔT = 2ºC
Replacing these values in (1) we get:

$q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)$

B)

Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.
Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

$q_{l} = c_{Al} * m_{Al} * \Delta T (3)$

⇒ $-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)$

$c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)$

which is pretty close to the Aluminum's accepted specific heat value of 0.900 J/gºC.

8 0

3 years ago