V=84.0 mL = 84.0 cm³
m=609.0 g
p=m/v
p=609.0/84.0=7.25 g/cm³
<span>Given in the question-
1 mole of cyclohexanol = > 1 mole of cyclohexene
Molar mass 100.16 g/mol
moles of cyclohexanol = .240 / 100.16= 0.002396 moles
Molar mass 82.143 g/mol
moles of cyclohexene formed @100 % yield = 0.002396
Molar mass 82.143 g/mol
mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g
bur we have .138g
so % yield = .138 / .197 = 70.0 %
Ans- 70 percentage yield of cyclohexene.</span>
It allowed him to realize that the mass of an atom is concentrated at its center because the atoms mostly went through the foil but some were deflected. He also realized that an atom probably wasn't just empty space and scattered electron and it had a positive center.
Answer:
The amount of sodium in this sample = 32.4 grams
Explanation:
Mass of Sodium = 23 g/mol
Mass of Chlorine = 35.5 g/mol
Mass of NaCl = 35.5 g/mol
Fraction of Na in NaCl = 
=0.648
We are given a sample of 50 grams of sodium chloride.
The amount of sodium in this sample = 
The amount of sodium in this sample = 
The amount of sodium in this sample = 32.4 grams
Answer:
pH change is -0.07
Explanation:
Using H-H equation for acetic acid:
pH = pKa + log [Acetate salt] / [Acetic acid]
Replacing:
pH = 4.74 + log[1.188M] / [1.188M]
pH = 4.74
The HCl reacts with sodium acetate producing acetic acid, thus:
HCl + CH₃COONa → CH₃COOH + NaCl
That means the final moles of sodium acetate are initial moles - moles of HCl and moles of acetic acid are initial moles + moles of HCl.
As the volume of the buffer is 1.0L, initial moles of both substances are 1.188moles. After reaction, the moles are:
sodium acetate: 1.188mol - 0.1mol = 1.088mol
Acetic acid: 1.188mol + 0.1mol = 1.288mol
Using again H-H equation:
pH = 4.74 + log[1.088M] / [1.288M]
pH = 4.67
pH change is: 4.67 - 4.74 = -0.07
