Question

Mg2+,Cr4+,I-,O2- formulas

Answer 1

Answer:

$MgI_2\\\\MgO\\\\CrI_4\\\\ CrO_2$

Explanation:

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In this case, we can notice that among the given ions, Mg2+ and Cr4+ are cations and I- and O2- are anions, thus, for each resulting compound we switch the oxidation states as subscripts to get:

$Mg^{2+}I^- \rightarrow MgI_2\\\\Mg^{2+}O^{2-} \rightarrow MgO\\\\Cr^{4+}I^-\rightarrow CrI_4\\\\Cr^{4+}O^{2-}\rightarrow CrO_2$

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