A red car passes a blue car. Which is true?

Brayden and Riku now use their skills to work a problem. Find the equivalent resistance, the current supplied by the battery and

Liono4ka [1.6K]

a) $5 \Omega$ , 1.6 A

b) $6 \Omega$ , 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

$R=R_1+R_2$

where

$R_1=4\Omega$

$R_2=1 \Omega$

Therefore, the equivalent resistance is

$R=4+1=5 \Omega$

Now we can use Ohm's Law to find the current flowing through the circuit:

$I=\frac{V}{R}$

where

V = 8 V is the voltage supplied by the battery

$R=5\Omega$ is the equivalent resistance of the circuit

Substituting,

$I=\frac{8}{5}=1.6 A$

The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.

b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

$R=R_1+R_2+R_3$

where:

$R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega$

Substituting, we find the equivalent resistance:

$R=4+1+1=6 \Omega$

Now we can find the current through the circuit by using again Ohm's Law:

$I=\frac{V}{R}$

where

V = 8 V is the voltage supplied by the battery

$R=6\Omega$ is the equivalent resistance

Substituting,

$I=\frac{8}{6}=1.33 A$

And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.

3 0

3 years ago

What is mass loss and how does it figure in the death of a star? is the sun undergoing mass loss

Debora [2.8K]

111122 is the mass of the star

8 0

4 years ago

Not only did Skid get shot out of a cannon when he was a clown in the circus, but he was also launched into the air by a vertica

tiny-mole [99]

Answer:

v = 16.11 m / s

Explanation:

For this exercise we must use the principle of conservation of energy. We set a reference system on the part of the platform without elongation

starting point. When the spring is compressed

Em₀ = K_e + U = ½ k x² + m g x ’

final point. The point where it leaves the platform

Em_f = K = ½ m v²

energy is conserved

Em₀ = Em_f

½ k x² + m g x ’= ½ m v²

v² = $\frac{k}{m}$ x² + g x

let's calculate

v² = $\frac{8700}{55}$ 1.25² + 9.8 1.25

v² = 247.159 + 12.25 = 259.409

v = 16.11 m / s

8 0

3 years ago

Many cultures experience music with their whole:

coldgirl [10]

Answer:

entertaining form of repetition

Explanation:

=>

7 0

3 years ago

Read 2 more answers

From t=0 onwards what happens to the voltage across the inductor annd the curreent through the inductor relative to their values

gregori [183]

From t=0 onwards I changes slowly and V changes abruptly across the inductor.

At time t=0, the voltage across the inductor equalises the battery voltage; nevertheless, Lenz's Law states that this induced EMF will always be opposed to the polarity of the battery. The voltage across the inductor is equivalent to the voltage of a battery because the inductor at time zero behaves like a second battery of the same voltage linked in reverse.

Because current can never be zero, voltage across the inductor decreases with time. If it did, there would be no back EMF to stop the current from flowing through the inductor because the magnetic field would not be changing. As a result, the inductor will become less of an open circuit as the current increases over time. The inductor will essentially behave like a resistor.

Learn more about inductor here:

brainly.com/question/15893850

#SPJ4

3 0

2 years ago