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noname [10]
1 year ago
8

From t=0 onwards what happens to the voltage across the inductor annd the curreent through the inductor relative to their values

.
Physics
1 answer:
gregori [183]1 year ago
3 0

From t=0 onwards I changes slowly and V changes abruptly across the inductor.

At time t=0, the voltage across the inductor equalises the battery voltage; nevertheless, Lenz's Law states that this induced EMF will always be opposed to the polarity of the battery. The voltage across the inductor is equivalent to the voltage of a battery because the inductor at time zero behaves like a second battery of the same voltage linked in reverse.

Because current can never be zero, voltage across the inductor decreases with time. If it did, there would be no back EMF to stop the current from flowing through the inductor because the magnetic field would not be changing. As a result, the inductor will become less of an open circuit as the current increases over time. The inductor will essentially behave like a resistor.

Learn more about inductor here:

brainly.com/question/15893850

#SPJ4

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Consider an opaque horizontal plate that is well insulated on its back side. The irradiation on the plate is 2500 W/m2, of which
GuDViN [60]

Answer:

i. 0.34

ii. 0.4

iii. 1700 w/m²

iv. 2211.36 w/m²

Explanation:

Given that

Irradiation of the plate, G = 2500 w/m²

Reflected rays, p = 500 w/m²

Emissive power, E = 1200 w/m²

See attachment for calculations

8 0
4 years ago
Which branch of science involves the study of matter and energy
Olin [163]
Physics<span> is a natural science that involves the study of matter and its motion through space time, along with related concepts such as energy and force.</span>
6 0
3 years ago
Read 2 more answers
When the switch is closed, what happens to the current in the circuit? (The intrinsic resistance of the inductor is zero.)
Hitman42 [59]
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>When the switch is closed, the current instantaneously becomes 1.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
If the velocity of a long jumper during take-offat an angle of 30 degrees is 42 f/s, how fast is he moving forward (Vx) and how
Arturiano [62]

Answer:

Vx=  11.0865(m/s)

Vy=  6.4008(m/s)

Explanation:

Taking into account that 1m is equal to 0.3048 ft, the takeoff speed in m / s will be:

V= 42(ft/s) × 0.3048(m/ft) = 12.8016(m/s)

The take-off angle is equal to 30 °, taking into account the Pythagorean theorem the velocity on the X axis will be:

Vx= 12.8016 (m/s) × cos(30°)= 11.0865(m/s)

And for the same theorem the speed on the Y axis will be:

Vy= 12.8016 (m/s) × sen(30°)= 6.4008(m/s)

5 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
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