Answer:
a dog walking or their phone rings or heard a neighbor talking to them
Answer:
M= F^n / a+g
Explanation:
This shows correctly Newton’s second law, where sum of forces is divided by mass is equal to acceleration. Also mass can’t be negative so F^n is positive.
(a) The plastic rod has a length of L=1.3m. If we divide by 8, we get the length of each piece:

(b) The center of the rod is located at x=0. This means we have 4 pieces of the rod on the negative side of x-axis, and 4 pieces on the positive side. So, starting from x=0 and going towards positive direction, we have: piece 5, piece 6, piece 7 and piece 8. Each piece is 0.1625 m long. Therefore, the center of piece 5 is at 0.1625m/2=0.0812 m. And the center of piece 6 will be shifted by 0.1625m with respect to this:

(c) The total charge is

. To get the charge on each piece, we should divide this value by 8, the number of pieces:

(d) We have to calculate the electric field at x=0.7 generated by piece 6. The charge on piece 6 is the value calculated at point (c):

If we approximate piece 6 as a single charge, the electric field is given by

where

and d is the distance between the charge (center of piece 6, located at 0.2437m) and point a (located at x=0.7m). Therefore we have

poiting towards the center of piece 6, since the charge is negative.
(e) missing details on this question.
Produce power through the circuit.
Given: Heat Qout means useful work = 2800 J
Heat Qin = 8900 J
Required; Efficiency = ?
Formula: Efficiency = Qout/Qin = x 100%
= 2800 J/8900 J = 0.3146 X 100 %
Efficiency = 31.46%