All categories

2 years ago

Many cultures experience music with their whole:

Physics

2 answers:

coldgirl [10]2 years ago

7 0

Answer:

entertaining form of repetition

Explanation:

ivanzaharov [21]2 years ago

7 0

Entertaining form of repetition , I think!

You might be interested in

The chemical symbol for sulfuric acid is H2SO4. How many atoms are contained in each molecule of sulfuric acid?

cricket20 [7]

You know from looking at the molecular formula that one molecule of H2SO4 contains 2 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen.

5 0

3 years ago

The A string of a violin is a little too tightly stretched. Beats at 4.00 per second are heard when the string is sounded togeth

Basile [38]

Answer:

$T=2.5*10^{-3}s$

Explanation:

From the question we are told that:

Beat frequency $F_b=4$

Frequency $F=400Hz$

Generally the equation for Frequency of the violin is mathematically given by

$f_v=F_b+F$

$f_v=4+400Hz$

$f_v=404Hz$

Therefore the period of the violin string oscillations is

$T=\frac{1}{f_v}$

$T=\frac{1}{404}$

$T=2.5*10^{-3}s$

3 0

3 years ago

The apple became weightless when it fell...

Tems11 [23]

The answer I believe would be a sorry if I’m wrong

3 0

3 years ago

Read 2 more answers

On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the

Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

$\frac{F_E}{F_G}=\frac{qE}{mg}$ (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

$\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764$

Then, the gravitational force is 0.764 times the electric force on the particle

The acceleration of the particle is obtained by using the second Newton law:

$F_E-F_G=ma\\\\a=\frac{qE-mg}{m}$

you replace the values of all variables:

$a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}$

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0

3 years ago

Delivery trucks that operate by making use of energy stored in a rotating flywheel have been used in Europe. The trucks are char

Marta_Voda [28]

Answer:

KE = 2.535 x 10⁷ Joules

Explanation:

given,

angular speed of the fly wheel = 940 rad/s

mass of the cylinder = 630 Kg

radius = 1.35 m

KE of flywheel = ?

moment of inertia of the cylinder

$I = \dfrac{1}{2}mr^2$

= $\dfrac{1}{2}\times 630\times 1.35^2$

= 574 kg m²

kinetic energy of the fly wheel

$KE = \dfrac{1}{2}I\omega^2$

$KE =\dfrac{1}{2}\times 574\times 940^2$

KE = 2.535 x 10⁷ Joules

the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules

5 0

3 years ago