Answer:
m = 9795.9 kg
Explanation:
v = 35 m/s
KE = 6,000,000 J
Plug those values into the following equation:
6,000,000 J = (1/2)(35^2)m
---> m = 9795.9 kg
What is the efficiency of the machine if the input is 263 J and the output is 142 J?
1 answer:
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Answer:
The value is
Explanation:
From the question we are told that
The mass of the object is
The unstressed length of the string is
The length of the spring when it is at equilibrium is
The initial speed (maximum speed)of the spring when given a downward blow
Generally the maximum speed of the spring is mathematically represented as
Here A is maximum height above the floor (i.e the maximum amplitude)
and is the angular frequency which is mathematically represented as
So
=>
Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as
=>
=>
Generally at equilibrium position the net force acting on the spring is
=>
=>
So
=>