Answer:
Explanation:
1.2(0) + 3(0.8) + 1.4(0.8/2) / (1.2 + 3 + 1.4) = 0.5285714... ≈ 0.53 m
Explanation:
It's displacement would be negative
displacement is a vector quantity.
'Backwards', we can assume, would be negative.
and forwards, positive. So going backwards would mean a negative displacement.
Answer:
Weight of the car, normal force, drag force
Explanation:
The forces acting on the car are:
- The normal force which acts perpendicularly to the downhill plane
- The weight of the car which acts vertically downwards
- The drag force due to air resistance which acts in opposition to the motion of the car
Friction is ignored, so the force due to friction is assumed negligible
Referring to Compton scattering
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)
7.19 ˣ 10⁻¹²m
The increased potential is given by
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)
173kV.
