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scoundrel [369]
3 years ago
5

a wagon of mass 42 kg is pushed by a student a distance of 12.2 meters, and 297 j of work was sone on the wagon how much force d

id the student apply assuming that it was constant
Physics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

Force=2.484 N

Explanation:

f =  \frac{w}{gh}  \\  =  \frac{297}{9.8 \times 12.2} \\  f = 2.484 \: n

Hope it helped

PLS mark BRAINLIEST

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Vitek1552 [10]
First we need to know the equation:
F= Mass times acceleration
F = 2.0 kg times 5.0 m/s^2 
multiply them to get the net force!
F= 10 N 
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7 0
4 years ago
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A thin uniform rod (length = 1.2 m, mass = 2.0 kg) is pivoted about a horizontal, frictionless pin through one end of the rod. (
Anika [276]

Answer:

a=9.8 rad/s^{2}

Explanation:

Torque, \tau is given by

\tau=Fr where F is force and r is perpendicular distance

R=0.5Lcos\theta where \theta is the angle of inclination

Torque, \tau can also be found by

\tau=Ia where I is moment of inertia and a is angular acceleration

Therefore, Fr=Ia and F=mg where m is mass and g is acceleration due to gravity

Making a the subject, a=\frac {Fr}{I}=\frac {mgr}{I} and already I is given as  

I=\frac {mL^{2}}{3} and r is 0.5Lcos\theta hence  

a=\frac {0.5mgLcos\theta}{1/3 mL^{2}}

a=\frac {3gcos\theta}{2L}

Taking g as 9.81, \theta is given as 37 and L is 1.2

a=\frac {3*9.81cos37}{2*1.2}=9.7932679419

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4 0
3 years ago
How does an understanding of plate motion help scientists
Arte-miy333 [17]

Answer:

advance in the understanding of cellular movement

Explanation:

All organisms are formed from cells, "understanding how cells are able to interact with other cells during development helps us understand how tissues and organs are established and, consequently, how the shape arises in embryos," explains Germán Reig

6 0
4 years ago
Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
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Answer:

Δu=1300kJ/kg  

Explanation:

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Is saturated vapor at initial pressure we have

p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)

Process 2-3 is a constant volume process

p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

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3 0
3 years ago
Note that the simulation allows you to also display the force of the smaller moon
Lelu [443]

the force that the planet exerts on the moon is equal to the force that the moon exerts on the planet

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If we apply this law to this situation, this means that the force that the planet exerts on the moon is equal to the force that the moon exerts on the planet.

Learn more about gravitational force:

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#LearnwithBrainly

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