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lbvjy [14]
3 years ago
12

Describe two ways unbalanced forces help you in your day to day life.

Physics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

  1. we need unbalance force to lift objects
  2. we need unbalance force to drag objects
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To suck lemonade of density 1040 kg/m3 up a straw to a maximum height of 4.94 cm, what minimum gauge pressure (in atmospheres) m
Lady bird [3.3K]

Answer:

The minimum gauge pressure is 0.4969 atm.

Explanation:

Given that,

Density = 1040 kg/m³

Height = 4.94 cm

We need to calculate the pressure

Using formula of pressure

P_{g}=\rho g h

Where, \rho=density

h = height

Put the value into the formula

P_{g}=1040\times9.8\times4.94

P_{g}=50348.48\ Pa

Pressure in atmospheres

1\ atm =101.3\ kPa

P_{g}=\dfrac{50348.48}{101325}

P_{g}=0.4969\ atm

Hence, The minimum gauge pressure is 0.4969 atm.

7 0
3 years ago
Read 2 more answers
A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w
inessss [21]

Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is v=\frac{d}{t}, where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is d=v\cdot t

Now, the distance equation for the man would be:

d_{man}=v_{man}\cdot t=1.6\cdot t

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)

For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

d_{man}=d_{dog}

1.6\cdot t=3\cdot (t-1.8)

1.6\cdot t=3\cdot t-5.4

1.4\cdot t=5.4

t=\frac{5.4}{1.4}

t=3.8571s

The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

d_{man}=1.6\cdot t=1.6\cdot (3.8571)

d_{man}=6.1714m

Finally, the dog catches up with the man 6.1714m later.

6 0
3 years ago
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Answer:

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Explanation:

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3 years ago
A system of pulleys is used to raise a load of bricks that weighs 1,700 newtons. The force applied to the pulley is 340 newtons.
Law Incorporation [45]
By definition, we have that the mechanical advantage is given by the following equation:
 MA =  \frac{W}{T} 

 Where,
 W: is the load
 T: is the tension
 Substituting the values in the given equation we have:
 MA = \frac{1700}{340}
 MA = 5

 Therefore, the mechanical advantage is equal to 5.
 Answer:
 The mechanical advantage of this machine is:
 MA = 5
4 0
3 years ago
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When buying a car, you tell the salesman that you want to make sure the car can go from 0 miles per hour to 60 miles per hour in
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Acceleration....................................... <span />
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