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3 years ago

Name 7 characteristics that are unique to mammals.

Physics

2 answers:

lana66690 [7]3 years ago

5 0

Answer:

The presence of hair or fur.

Sweat glands.

Glands specialized to produce milk, known as mammary glands.

Three middle ear bones.

A neocortex region in the brain, which specializes in seeing and hearing.

Specialized teeth.

A four-chambered heart.

Explanation:

These are characteristics of mammals.

SSSSS [86.1K]3 years ago

3 0

Mammals are endothermic vertebrates
Have hair and fur on the body
Have mammary glands
Four chambered hearts
Have sebaceous (fat secreting glands), sudoriferus (sweat), and scent glands.
Have heterodont dentation (different types of teeth)
Posses diaphragm
Posses one single jaw bone
Have three small bones in the middle of the ear

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A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5

Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting into the equation, we have;

$S =20*5 + \frac{1}{2}*(-4)*5^{2}$

$S =100 + (-2)*25$

$S =100 - 50$

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

$V^{2} = U^{2} + 2aS$

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$V^{2} = 20^{2} + 2(-4)*50$

$V^{2} = 400 - 400$

$V^{2} = 0$

V = 0m/s

Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.

5 0

3 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the fir

tia_tia [17]

Answer:

7560 Joules

Explanation:

$m_1$ = Mass of first car = $1.5\times 10^5\ kg$

$m_2$ = Mass of second car = $2\times 10^5\ kg$

$u_1$ = Initial Velocity of first car = 0.3 m/s

$u_2$ = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

As linear momentum of the system is conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1.5\times 10^5\times 0.3 + 2\times 10^5\times -0.12}{1.5\times 10^5 + 2\times 10^5}\\\Rightarrow v=0.06\ m/s$

Energy lost is

$\Delta E=\Delta E_i-\Delta E_f\\\Rightarrow \Delta=\frac{1}{2}(m_1u_1^2 + m_2u_2^2-(m_1+m_2)v^2)\\\Rightarrow \Delta=\frac{1}{2}(1.5\times 10^5\times 0.3^2 + 2\times 10^5\times (-0.12)^2-(1.5\times 10^5 + 2\times 10^5)\times 0.06^2)\\\Rightarrow \Delta=7560\ J$

The Energy lost in the collision is 7560 Joules

7 0

2 years ago

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Tcecarenko [31]

A. Food chain

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3 0

1 year ago

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Dmitrij [34]

Hey Friends
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3 years ago

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Tatiana [17]

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3 years ago