Answer:
The tension in the two ropes are;
T1 = 23.37N T2 = 35.47N
Explanation:
Given mass of the object to be 4.2kg, the weight acting on the bag will be W= mass × acceleration due to gravity
W = 4.2×10 = 42N
The tension acting on the bag plus the weight are three forces acting on the bag. We need to find tension in the two ropes that will keep the object in equilibrium.
Using triangular law of force and sine rule to get the tension we have;
If rope 1 is at 57.6° with respect to the vertical and rope 2 is at 33.8° with respect to the vertical, our sine rule formula will give;
T1/sin33.8° = T2/sin57.6° = 42/sin{180-(33.8°+57.6°)}
T1/sin33.8° = T2/sin57.6° = 42/sin88.6°
From the equality;
T1/sin33.8° = 42/sin88.6°
T1 = sin33.8°×42/sin88.6°
T1 = 23.37N
To get T2,
T2/sin57.6°= 42/sin88.6°
T2 = sin57.6°×42/sin88.6°
T2 = 35.47N
Note: Check attachment for diagram.
<span>The correct answer is: C) refraction.
Hope this helps :)</span>
Answer:
1 m
Explanation:
Given
The mirror is a concave mirror.
Radius of curvature = 2 m
Now, for a parallel beam after reflection occurs, the object should be placed at the focus of the mirror.
We know, focal length = radius of curvature / 2
= 2 / 2
= 1
Thus the focal length is 1 m.
Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.
Answer:
A=50mΩ
B≅50mΩ
Explanation:
A) To answer this question we have to use the Current Divider Rule. that rule says:
(1)
Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.
We now have a set of two resistor in parallel, so:
(2)
where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).
substituting and rearranging (2)
(3)
Now substituting (3) in (1).
solving this, The value of R1 is: 50mΩ
This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.
Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ
If you substitude this values on (2) Req. will be 49.97 mΩ.
