Find the screenshots in the attachment for complete solution. Follow the sequence
Answer
given,
B = 6.40 mm , L = 26 cm , τ = 3.90 × 10⁻² s
general wave equation
y = A cos (k x - ωt)
where A is the amplitude of the
a) Amplitude of the given wave
B = 6.40 mm
b) Wavelength of the given wave
λ = L
λ = 26 cm
c) wave frequency
f = 25.64 Hz
d) speed of wave will be equal to
v = f λ
v = 25.64 x 0.26
v = 6.67 m/s
e) direction of propagation will be along +ve x direction because sign of k x and ωt is same as general equation.
please, give the question properly.
Answer:
143.352 watt.
Explanation:
So, in the question above we are given the following parameters or data or information that is going to assist us in answering the question above efficiently. The parameters are:
"A 1.8 m wide by 1.0 m tall by 0.65m deep home freezer is insulated with 5.0cm thick Styrofoam insulation"
The inside temperature of the freezer = -20°C.
Thickness = 5.0cm = 5.0 × 10^-2 m.
Step one: Calculate the surface area of the freezer. That can be done by using the formula below:
Area = 2[ ( Length × breadth) + (breadth × height) + (length × height) ].
Area = 2[ (1.8 × 0.65) + (0.65 × 1.0) + (1.8 × 1.0)].
Area = 7.24 m^2.
Step two: Calculate the rate of heat transfer by using the formula below;
Rate of heat transfer =[ thermal conductivity × Area (T1 - T2) ]/ thickness.
Rate of heat transfer = 0.022 × 7.24(25+20)/5.0 × 10^-2 = 143.352 watt.
Answer:
4.96 eV
Explanation:
Recall the Einstein photoeletric equation;
KE = E - Wo
Where;
KE = kinetic energy of the ejected photoelectron
E= energy of the incident photon
Wo = Work function
But
KE = eV= 1.6 * 10^-19 C * 7 V /1.6 * 10^-19 C = 7 eV
E = hf/e = 6.6 * 10^-34 * 2.9 ✕ 10^15 Hz/1.6 * 10^-19
E = 11.96 eV
Hence;
Wo = E - KE
Wo = 11.96 eV - 7eV
Wo = 4.96 eV