<u>Answer:</u> The moles of oxygen and carbon dioxide in air is
and
respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of atmosphere = 
Average molar mass of atmosphere = 28.96 g/mol
Putting values in above equation, we get:

We know that:
Percent of oxygen in air = 21 %
Percent of carbon dioxide in air = 0.0415 %
Moles of oxygen in air = 
Moles of carbon dioxide in air = 
Hence, the moles of oxygen and carbon dioxide in air is
and
respectively
<h3>
Answer:</h3>
The Equilibrium would shift to produce more NO
<h3>
Explanation:</h3>
The reaction is;
N₂(g) + O₂(g) ⇆ 2NO(g)
- When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
- From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
- For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
- Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.
Test tube of ammonium chloride (NH4Cl) being heated over a bunsen burner flame. Ammonium chloride decomposes readily when heated, but condenses in the cooler area at the top of the test tube. This is a reversible reaction, where the ammonium chloride decomposes into the gases ammonia (NH3) and hydrogen chloride (HCl).
B- 8.2980
C- 11.2603
F- 17.4228
Li- 5.3917
Na- 5.1391
I would say your answer is Na.