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3 years ago

Maria rolls a die. What is the chance of her rolling a 4?

Chemistry

2 answers:

Alex73 [517]3 years ago

8 0

If it's a normal 6 sided dice, it'd be 1/6

Citrus2011 [14]3 years ago

3 0

Idk ask your teacher dumbo

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With the given chemical compounds, what is the balanced chemical equation when lit with fire?

Alchen [17]

Answer:

Russia es el mejor pais? Vladimir Putin, es el mejor presidente del mundo

8 0

3 years ago

An "empty" container is not really empty if it contains air. How may moles of nitrogen are in an "empty" two-liter cola bottle a

Lisa [10]

Answer:

1. 0.0637 moles of nitrogen.

2. The partial pressure of oxygen is 0.21 atm.

Explanation:

1. If we assume ideal behaviour, we can use the Law of ideal gases to find the moles of nitrogen, considering that air composition is mainly nitrogen (78%), oxygen (21%) and argon (1%):

$V_{N_2}=V_{T}\times 0.78=2L \times 0.78 =1.56 L\\PV=nRT\\n_{N_2}=\frac{PV}{RT}=\frac{1 atm\times 1.56 L}{0.0821\frac{atmL}{molK}\times 298 K}\\n_{N_2}= 0.0637 mol$

2. Now, in order to find he partial pressure of oxygen we need to find the total moles of air, and then the moles of oxygen. Then, we use these results to determine the molar fraction of oxygen, to multiply it with total pressure and get the partial pressure of oxygen as follows:

$n_{total}=\frac{1 atm \times 2L}{0.0821 \frac{atmL}{molK}298K}=0.0817 mol$

$V_{O_2}=2L \times 0.21 = 0.42 L\\n_{O_2}=\frac {1atm \times 0.42 L}{0.0821 \frac{atm L}{mol K}298 K}=0.0172 mol\\X_{O_2}=\frac{n_{O_2}}{n_{total}}=\frac{0.0172 mol}{0.0817 mol}= 0.21$

$P_{O_2}=X_{O_2} \times P = 1 atm \times 0.21 = 0.21 atm$

As you see, the molar fraction and volume fraction are the same because of the assumption of ideal behaviour.

3 0

3 years ago

How many kilocalories of heat are released when 75 g of steam at 100 degrees Celsius is converted to ice at 0 degrees Celsius?

VikaD [51]

Answer:

∴ Q = -7.52kCal

Explanation:

Using the formula for specific heat capacity:

Q = mcΔT

where ΔT = change in temperature (final - initial) = (0 - 100)°C = -100°C

m = mass (g) = 75g

c = specific heat capacity = 4.2 J/g°C in water

⇒ Q = 75 × 4.2 × -100

= -31,500J

But 1J - 0.000239kCal

<u>∴ Q = -7.52kCal</u>

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Let me know if I can be of further assistance.

5 0

3 years ago

John dalton proposed a theory that all matter is made up of individuals particles which cannot be divided. what were those parti

juin [17]

The particles are atoms, his theory is the atomic theory

3 0

3 years ago

Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10

nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8

<h2><u>Answer: [OH-] = 1.3 x 10^-8</u></h2>

4 0

3 years ago