The momentum of the water balloon at the given speed is 7.2 kgm/s.
The given parameters:
- <em>Speed of the water balloon, v = 18 m/s</em>
- <em>Mass of the balloon, m = 0.4 kg</em>
The momentum of the water balloon is calculated as follows;
P = mv
<em>Substitute the given values of </em><em>mass </em><em>and </em><em>velocity </em><em>as follows;</em>
P = 0.4 x 18
P = 7.2 kg m/s.
Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.
Learn more about momentum here: brainly.com/question/7538238
Since angular speed is persistent, v/r is constant.
Where:
v is tangential speed;
and
r is distance from
axis.
Then equate v/r in both cases to get v in the second case.
Hence, speed = 2.2 x 2.1 / 1.4 meters
= 3.3 meters / seconds
Alternative solution would be:
w = 2.2 / 1.4 = 1.57
v = rw = 2.1 x 1.57 = 3.3 meters / seconds
Answer:
the red at the bottom should not count, but the red at the top is the least dense because it floats upon the other liquids
Explanation:
hope this helps
Answer:
Explanation:
m = Mass of each the cars = 
= Initial velocity of first car = 3.46 m/s
= Initial velocity of the other two cars = 1.4 m/s
v = Velocity of combined mass
As the momentum is conserved in the system we have
Speed of the three coupled cars after the collision is .
As energy in the system is conserved we have
The kinetic energy lost during the collision is .
Answer:
because of their web feet
Explanation:
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