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Softa [21]
3 years ago
7

How do you think speed affects car and driver safety?

Physics
1 answer:
blondinia [14]3 years ago
4 0
An increase in average speed of 1 km/h typi- cally results in a 3% higher risk of a crash involving injury, with a 4–5% increase for crashes that result in fatalities. — Speed also contributes to the severity of the impact when a collision does occur. Hope this helps!
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At which location would an objects weight be the greatest. 1.pluto 2.earth 3.sun 4.moon
Maslowich

Weight of the object is given as

Weight = mg

so weight of the object will be maximum where gravity(g) will be maximum

so here out of all given four the gravity "g" will be maximum at the surface of SUN as we know that sun will be of maximum mass out of all four planets

as we know that

g = \frac{GM}{R^2}

so correct answer will be

3. SUN

8 0
4 years ago
Read 2 more answers
What is the KE of a 4 kg rock rolling at 10 m/s? KE = 1/2 mv2
Kipish [7]

Answer:

200J

Explanation:

0.5 *4 * 10 * 10

=200J

8 0
3 years ago
A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
What would result from under-coverage?
Sunny_sXe [5.5K]
C. a lack of accurate results


hope this helps
6 0
3 years ago
A ball is launched from ground level and hits the ground again after an elapsed time of 4 seconds and after traveling a horizont
Mumz [18]

Answer:

a. It is constant the whole time the ball is in free-fall

Explanation:

If we divide the movement on its vertical and horizontal components, and we concentrate on the vertical component, let's call x-component, and analyze Newton's second's law:

\sum\overrightarrow{F_{x}}=m\overrightarrow{a_{x}}

with \sum\overrightarrow{F_{x}}, a_{x} the acceleration on horizontal direction and m the mass of the ball, because the only force acting on the object is gravity that is always vertical, there're not forces on the horizontal direction that means \sum\overrightarrow{F_{x}}=0 and by (1) that implies a_{x}=0 there's not acceleration on horizontal direction.

Because acceleration is the rate at what velocity changes and there's no acceleration, there's no change in velocity, in other words velocity is constant on horizontal direction.

6 0
3 years ago
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