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Setler [38]
3 years ago
8

A merry-go-round at a playground is a circular platform that is mounted parallel to the ground and can rotate about an axis that

is perpendicular to the platform at its center. the angular speed of the merry-go-round is constant, and a child at a distance of 1.4 m from the axis has a tangential speed of 2.2 m/s. what is the tangential speed of another child, who is located at a distance of 2.1 m from the axis?
Physics
1 answer:
julsineya [31]3 years ago
3 0

Since angular speed is persistent, v/r is constant.
Where:

 v is tangential speed; and

 r is distance from axis.

 

Then equate v/r in both cases to get v in the second case.

Hence, speed = 2.2 x 2.1 / 1.4 meters

= 3.3 meters / seconds

 

Alternative solution would be:

w = 2.2 / 1.4 = 1.57

v = rw = 2.1 x 1.57 = 3.3 meters / seconds 

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The component of the external magnetic field along the central axis of a 18 18 turn circular coil of radius 27.0 27.0 cm decreas
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Answer:

Induced current I = 0.44 A

Explanation:

given data

no of turn N = 18

radius  = 27.0 cm

resistance of the coil = 4.50 Ω

time = 2.90 s

magnetic field  = 1.90 T to 0.500 T

solution

we get Induced EMF that is

E = - dφ ÷ dt    ..............1

E = - N × A × (B2 - B1) ÷ Δt

E = N × A × (B1 - B2) ÷ Δt

area of cross section of the coil A = π × r²

area of cross section = 3.14 × (0.27)²

area of cross section = 0.228 m²

Initial magnetic field B1   = 1.9 T

and  

Final magnetic field B2   = 0.5 T

time      Δt = 3.7 s

put here value and we get

E  =  \frac{18 \times 0.228 \times (1.9-0.5)}{2.90}  

E  = 1.98 V

and  

Induced current I is express as

Induced current I = E  ÷ R    ................2

Induced current I = \frac{1.98}{4.5}

Induced current I = 0.44 A

3 0
2 years ago
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