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Anettt [7]
3 years ago
10

HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start

with 155,8 grams of
iron (Fe), how many grams of copper (Cu) will be produced?
2Fe + 3CuCl2 à 2FeCl3 + 3Cu
Chemistry
1 answer:
Helga [31]3 years ago
7 0

Answer: 30.978

Explanation:

From the equation 2 moles of Fe will result in 3 moles copper

so .325 moles Fe will result in .4875 moles Cu

Cu weights 63.546 gm per mole

.4875 moles * 63.546 gm / mole = 30.978 gm of Cu

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An element has 3 electrons, 3 protons and 4 neutrons. What will be its atomic number and mass number? (​
stiv31 [10]

Answer:

its atomic number will be 3 and it's mass number will be 7. it is lithium

8 0
2 years ago
A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul
WITCHER [35]
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
5 0
3 years ago
A sample of water at 100°C is converted to steam after absorbing 820 kJ of heat. How grams of H2O are contained in the sample? A
Varvara68 [4.7K]
Since water is already at 100<span>°C all the energy is used to evaporate it. 
Now we can calculate how many </span>mols of water are evaporated with 820kJ.
N= \frac{820}{41} =20 mol
We calculated that we got 20 mols of water evaporated. Now, all we have to do is find how many grams is a mol of water. Molar mass of water is <span>20.16 g/mol.
</span>The final answer is:
m=20*20.16=403.2g




7 0
3 years ago
A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

We convert this to atm: 1 torr = 0.00132 atm

515.715 Torr = 515.715 * 0.00132 = 0.681 atm

8 0
3 years ago
Out of the 3 of these
Delvig [45]
Electrons can be transformed from on object to another , (can you mark me brainlyest)
6 0
3 years ago
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