_____________________________
Question: What is the formula of zinc sulphate?
Answer: The formula of zinc sulphate is ZnSO4. It contains one atom of zinc one atom of sulphur and four atom of Oxygen. It is colourless compound. It is an acidic salt which is formed by the reaction of Zinc Hydroxide and Sulphuric acid. It turns blue litmus paper into red which proves that it is acidic in nature.
_____________________________
0,15 moles of NaOH-------in------------1000ml
x moles of NaOH------------in--------100ml
x = 0,015 moles of NaOH
final volume = 150ml
0,015 moles of NaOH---in-------150ml
x moles of NaOH--------------in-----1000ml
x = 0,1 moles of NaOH
answer: 0,1mol/dm³ (molarity)
The chemical formula of the ionic compound is XY₂.
<h3>Ionic compounds</h3>
- Ionic compounds are compounds which are formed from the combination of negatively charged and positively charged ion.
- Positively charged ions are formed by loss of electrons
- Negatively-charged ions are formed from gain of electrons
<h3>Formation of ionic compounds</h3>
During the formation of the ionic compound between an ion X that has a charge of 2+ and ion Y has a charge of 1-, two negatively charged ions of Y are required to form a neutral ionic ionic compound when they react with X.
The chemical the formula of the ionic compound they form is as follows;
X²⁺ + 2Y⁻ ---> XY₂
Therefore, the chemical formula of the ionic compound is XY₂.
Learn more about ionic compounds at: brainly.com/question/13439771
Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,
CO + 2 H₂ → CH₃OH
Calculating Moles of CO:
According to equation,
32 g (1 mole) of CH₃OH is produced by = 1 Mole of CO
So,
3.60 × 10² g of CH₃OH is produced by = X Moles of CO
Solving for X,
X = (3.60 × 10² g × 1 Mole) ÷ 32 g
X = 11.25 Moles of CO
Calculating Moles of H₂:
According to equation,
32 g (1 mole) of CH₃OH is produced by = 2 Mole of H₂
So,
3.60 × 10² g of CH₃OH is produced by = X Moles of H₂
Solving for X,
X = (3.60 × 10² g × 2 Mole) ÷ 32 g
X = 22.5 Moles of H₂
Result:
3.60 × 10² g of CH₃OH is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.
