Answer:
% sodium= 13.6 % sodium
% carbon= 35.5 % carbon
% hydrogen= 4.7% hydrogen
% nitrogen = 8.3% nitrogen
% oxygen = 37.8 % oxygen
Explanation:
To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.
The molar mass of monosodium glutamate is 169.11 gmol-1
Hence;
Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium
Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon
Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen
Percent nitrogen = 14/169.11 gmol-1 × 100 = 8.3% nitrogen
Percent oxygen = 64/169.11 gmol-1 ×100 = 37.8 % oxygen
Answer: a) 
Explanation:
As we know that,
where,
q = heat released = -600.2 J
= mass of iron rod =100 g
= final temperature =
= initial temperature = ?
= specific heat of iron = 
Now put all the given values in equation, we get
![-600.2J=100\times 0.452J/g^0C\times (25.0-T_{initial})^0C]](https://tex.z-dn.net/?f=-600.2J%3D100%5Ctimes%200.452J%2Fg%5E0C%5Ctimes%20%2825.0-T_%7Binitial%7D%29%5E0C%5D)
Therefore, the initial temperature of iron rod was
The fluid filled area between the pleural layers is called the pleural cavity.
Answer:
B.
Explanation: Metal B contacted more rapidly then Metal A.
