Answer:
I think B no is correct orterwise Ano
1. s block elements have spherical s orbital as
their outermost orbital.
2. Since s orbital can accommodate a maximum of 2 electrons, each one of these elements have 1 or two electrons.
3. These s electrons are lost very easily to form
monopositive ions by Isoing one electron in the
outermost orbital or dipositive ions by losing 2
electrons.
4. They have low ionisation potentials and low electronegativities.
5. They are good conductors of heat and electricity, excepting H2 and He.
6. They are silvery, shiny metallic substances, (with the exception of hydrogen and helium which gaseous nonmetals).
7. They are malleable and ductile, i.e., we can
make sheets and wires from them, (exception:
H2, He)
8. They readily form ionic salts with most nonmetals.
hope it helps plzzz mark as brainliest
Asexual reproduction involves the production of offspring without the need for a secondary partner to contribute genetic information.
Pollination and mating are two forms of sexual reproduction, so B, C, and D are incorrect. A, because the new potato grows directly from the old without the contribution of new genetic material, asexually reproduces.
Answer:
(A) -117.48°C (B) 80.5368°C
Explanation:
It is given that density of ethanol is 0.789
volume of ethanol=89.8 mL
mass of ethanol = density of ethanol×volume = 0.789×89.8 = 70.8522 g
molar mass of ethylene glycol = 62 g/mole
therefore moles of ethylene glycol in 7.6 g of it = 7.7/62 = 0.1241 mole
molality = moles of ethylene glycol/mass of ethanol in kg
also Kf for ethanol = 1.99 C/m
And Kb for ethanol = 1.22 C/m
boiling point of ethanol = 78.4 °C
freezing point of ethanol = -114° C
(A) depression in freezing point = molality×Kf = 1.75153×1.99 = 3.4855
thus freezing point of solution = -114-3.4855= -117.48°C
(B) elevation in boiling point = molality×Kb = 1.75153×1.22 = 2.13686
thus boiling point of solution = 78.4+2.13686=80.5368°C
<h3>
Answer:</h3>
7.182K
<h3>
Explanation:</h3>
From the question we are given;
- Initial temperature, T1 = 275 K
- Final temperature, T2 = 395 K
- Initial volume, V1 = 5 L
We are required to calculate the final volume, V2
- Charles's law is the law that relates the volume of a gas and its temperature.
- It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
- Therefore;
To calculate, V2 we rearrange the formula;
Therefore, the ending volume will be 7.182K